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Top Forums Shell Programming and Scripting Write filenames into an array variable Post 302628679 by Chubler_XL on Tuesday 24th of April 2012 12:39:44 AM
Old 04-24-2012
Try this grep -Ev '^\.$|\.\.$' for your grep statement.

You can also populate the array in one go with:

Code:
#!/bin/bash
script_loc=/export/home/oracle/HY_DUMP
cd $script_loc
IFS=$'\n' testarray=( $(ls -1) )

 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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