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Top Forums Shell Programming and Scripting creating printf statement using user arguments Post 302627171 by kristinu on Friday 20th of April 2012 10:23:05 AM
Old 04-20-2012
Ahhh Yes.

In my situation I will be using "$@"

How can I modify this to exclude the last arguments, ot the last two arguments?

---------- Post updated at 08:53 AM ---------- Previous update was at 08:32 AM ----------

I have now coded the following:

Code:
length=$(($#-2))
 array="${@:1:$length}"
 echo "All Arguments except last two"
 printf "$frmt" "$array"
 

echo "All Arguments"
 printf "$frmt" "$@"


The problem is this:


"$@" allows the each parameter to become a single word, so that "$@" is equivalent to "$1" "$2", because some arguments will have contain embedded blanks.



However calling $array does not allow me to do things as "$@" does, even though the array manages to drop the last two arguments.

---------- Post updated at 09:23 AM ---------- Previous update was at 08:53 AM ----------

I managed to make it work using the following



Code:
printf "$frmt" "${@:1:$(($#-2))}"

 

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