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Homework and Emergencies Homework & Coursework Questions Problem with using using quote in awk script Post 302623255 by ymc1g11 on Friday 13th of April 2012 10:25:51 AM
Old 04-13-2012
Quote:
Originally Posted by Corona688
'cat argv' does not work inside awk. awk is not a shell language. Neither does grep or wc -l.

What does the output from a_script look like, and what do you want to do with it?
the output of a_script looks like the following:

Quote:
KW4912T.DOC
KW4912XS.doc
KW4912XT.pdf
KW4912GT.PDF
KW4912X.doc
KW4912ZX.doc
and my $argv[1] is actually an access log file, by using grep and the above line as argument, i want to find out how many times had the file been viewed. Yet some of the output of a_script might not been accessed b4, any help?
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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