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Top Forums Programming Problem with STL's std::set container parameter to the operator << () Post 302622643 by Corona688 on Thursday 12th of April 2012 11:41:14 AM
Old 04-12-2012
g++ tells you exactly what to do.

Code:
$ g++ iter.cpp
iter.cpp: In function 'std::ostream& operator<<(std::ostream&, const std::set<T, C, std::allocator<_CharT> >&) [with T = A, C = std::less<A>]':
iter.cpp:40:   instantiated from here
iter.cpp:21: error: dependent-name 'std::set::const_iterator' is parsed as a non-type, but instantiation yields a type
iter.cpp:21: note: say 'typename std::set::const_iterator' if a type is meant
iter.cpp: In function 'std::ostream& operator<<(std::ostream&, const std::set<T, C, std::allocator<_CharT> >&) [with T = A, C = compA]':
iter.cpp:41:   instantiated from here
iter.cpp:21: error: dependent-name 'std::set::const_iterator' is parsed as a non-type, but instantiation yields a type
iter.cpp:21: note: say 'typename std::set::const_iterator' if a type is meant

$

Code:
template<class T, class C>
std::ostream& operator << (std::ostream& os, const set<T, C>& s)
{
    typename std::set<T,C>::const_iterator itr=s.begin();

    for (int i = 0; i < s.size(); i++) {
  //      os << *itr++ << " ";
    }

    return os;
}


Last edited by Corona688; 04-12-2012 at 12:48 PM..
 

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std::decimal::decimal64(3cxx)											     std::decimal::decimal64(3cxx)

NAME
std::decimal::decimal64 - SYNOPSIS
Public Types typedef float __decfloat64 __attribute__ ((mode(DD))) Public Member Functions decimal64 (decimal32 d32) decimal64 (decimal128 d128) decimal64 (float __r) decimal64 (double __r) decimal64 (long double __r) decimal64 (int __z) decimal64 (unsigned int __z) decimal64 (long __z) decimal64 (unsigned long __z) decimal64 (long long __z) decimal64 (unsigned long long __z) decimal64 (__decfloat64 __z) __decfloat64 __getval (void) void __setval (__decfloat64 __x) decimal64 & operator*= (decimal32 __rhs) decimal64 & operator*= (decimal64 __rhs) decimal64 & operator*= (decimal128 __rhs) decimal64 & operator*= (int __rhs) decimal64 & operator*= (unsigned int __rhs) decimal64 & operator*= (long __rhs) decimal64 & operator*= (unsigned long __rhs) decimal64 & operator*= (unsigned long long __rhs) decimal64 & operator*= (long long __rhs) decimal64 & operator++ () decimal64 operator++ (int) decimal64 & operator+= (int __rhs) decimal64 & operator+= (decimal32 __rhs) decimal64 & operator+= (decimal64 __rhs) decimal64 & operator+= (decimal128 __rhs) decimal64 & operator+= (unsigned int __rhs) decimal64 & operator+= (long __rhs) decimal64 & operator+= (unsigned long __rhs) decimal64 & operator+= (long long __rhs) decimal64 & operator+= (unsigned long long __rhs) decimal64 & operator-- () decimal64 operator-- (int) decimal64 & operator-= (long __rhs) decimal64 & operator-= (int __rhs) decimal64 & operator-= (long long __rhs) decimal64 & operator-= (unsigned long long __rhs) decimal64 & operator-= (unsigned long __rhs) decimal64 & operator-= (decimal128 __rhs) decimal64 & operator-= (unsigned int __rhs) decimal64 & operator-= (decimal32 __rhs) decimal64 & operator-= (decimal64 __rhs) decimal64 & operator/= (decimal32 __rhs) decimal64 & operator/= (long long __rhs) decimal64 & operator/= (unsigned long long __rhs) decimal64 & operator/= (unsigned long __rhs) decimal64 & operator/= (decimal64 __rhs) decimal64 & operator/= (unsigned int __rhs) decimal64 & operator/= (decimal128 __rhs) decimal64 & operator/= (long __rhs) decimal64 & operator/= (int __rhs) Detailed Description 3.2.3 Class decimal64. Definition at line 310 of file decimal. Constructor &; Destructor Documentation std::decimal::decimal64::decimal64 (__decfloat64__z) [inline] Conforming extension: Conversion from scalar decimal type. Definition at line 334 of file decimal. Author Generated automatically by Doxygen for libstdc++ from the source code. libstdc++ Tue Nov 27 2012 std::decimal::decimal64(3cxx)
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