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Top Forums Programming Problem with STL's std::set container parameter to the operator << () Post 302621897 by royalibrahim on Wednesday 11th of April 2012 08:36:37 AM
Old 04-11-2012
Problem with STL's std::set container parameter to the operator << ()

Hi,

I have this following code which gives me error when compiling. The problem is happening at the point where I create a const_iterator inside the overloaded insertion operator (i.e) operator << () function. The template argument version of set is not correct I guess. Could anyone please pitch in and make this code working?

Code:
#include <iostream>
#include <set>

using namespace std;

class A {
public:
    int _i;
    A(int i) : _i(i) {}
    bool operator < (A a) const { return _i < a._i; }
};

class compA {
public:
    bool operator()(A a1, A a2) const { return (a1._i > a2._i); }
};

template<class T, class C>
std::ostream& operator << (std::ostream& os, const set<T, C>& s) {
    std::set<T, C>::const_iterator itr = s.begin();

    for (int i = 0; i < s.size(); i++) {
        os << *itr++ << " ";
    }

    return os;
}

int main() {
    set<A, less<A> > s1;
    set<A, compA> s2;

    s1.insert(A(9)); s1.insert(A(3)); s1.insert(A(-5)); s1.insert(A(3));
    s2.insert(A(2)); s2.insert(A(1)); s2.insert(A(7));

    cout << s1;
    cout << s2;
}


Last edited by royalibrahim; 04-16-2012 at 03:11 AM..
 

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std::decimal::decimal64(3)				     Library Functions Manual					std::decimal::decimal64(3)

NAME
std::decimal::decimal64 - SYNOPSIS
Public Types typedef float __decfloat64 __attribute__ ((mode(DD))) Public Member Functions decimal64 (decimal32 d32) decimal64 (decimal128 d128) decimal64 (float __r) decimal64 (double __r) decimal64 (long double __r) decimal64 (int __z) decimal64 (unsigned int __z) decimal64 (long __z) decimal64 (unsigned long __z) decimal64 (long long __z) decimal64 (unsigned long long __z) decimal64 (__decfloat64 __z) __decfloat64 __getval (void) void __setval (__decfloat64 __x) decimal64 & operator*= (decimal32 __rhs) decimal64 & operator*= (decimal64 __rhs) decimal64 & operator*= (decimal128 __rhs) decimal64 & operator*= (int __rhs) decimal64 & operator*= (unsigned int __rhs) decimal64 & operator*= (long __rhs) decimal64 & operator*= (unsigned long __rhs) decimal64 & operator*= (unsigned long long __rhs) decimal64 & operator*= (long long __rhs) decimal64 & operator++ () decimal64 operator++ (int) decimal64 & operator+= (int __rhs) decimal64 & operator+= (decimal32 __rhs) decimal64 & operator+= (decimal64 __rhs) decimal64 & operator+= (decimal128 __rhs) decimal64 & operator+= (unsigned int __rhs) decimal64 & operator+= (long __rhs) decimal64 & operator+= (unsigned long __rhs) decimal64 & operator+= (long long __rhs) decimal64 & operator+= (unsigned long long __rhs) decimal64 & operator-- () decimal64 operator-- (int) decimal64 & operator-= (long __rhs) decimal64 & operator-= (int __rhs) decimal64 & operator-= (long long __rhs) decimal64 & operator-= (unsigned long long __rhs) decimal64 & operator-= (unsigned long __rhs) decimal64 & operator-= (decimal128 __rhs) decimal64 & operator-= (unsigned int __rhs) decimal64 & operator-= (decimal32 __rhs) decimal64 & operator-= (decimal64 __rhs) decimal64 & operator/= (decimal32 __rhs) decimal64 & operator/= (long long __rhs) decimal64 & operator/= (unsigned long long __rhs) decimal64 & operator/= (unsigned long __rhs) decimal64 & operator/= (decimal64 __rhs) decimal64 & operator/= (unsigned int __rhs) decimal64 & operator/= (decimal128 __rhs) decimal64 & operator/= (long __rhs) decimal64 & operator/= (int __rhs) Detailed Description 3.2.3 Class decimal64. Definition at line 310 of file decimal. Constructor &; Destructor Documentation std::decimal::decimal64::decimal64 (__decfloat64__z) [inline] Conforming extension: Conversion from scalar decimal type. Definition at line 334 of file decimal. Author Generated automatically by Doxygen for libstdc++ from the source code. libstdc++ Tue Jun 10 2014 std::decimal::decimal64(3)
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