hi gurus!
i realize that my question shows my stupidness, but i need your help!
i have:
s_date=`date +%m-%d-%Y_%I%p`
variable and i need the same, but minus one hour..
what i made:
s_date=time(`date +%m-%d-%Y_%I%p`) - 3600
but i'm getting:
daily_exports.sh: line 20: syntax error near... (4 Replies)
hi,
i set up a script on my server to do a particular task once files from an external system are ftpd in the format compaq_20100110 (YYDDMM). Interestingly, the source of ftp is sending the files in the format e.g 20100109 i.e. previous date and for some reason this fails.kindly see my script... (2 Replies)
Hallo all i am trying to execute this script ...............
But this is throwing the error......
use of uninitialized value in subtraction in at icd_convert.pl line 156
use of uninitialized value in subtraction in at icd_convert.pl line 157
use of uninitialized value in subtraction in at... (1 Reply)
HI gurus...
I have a PERL file that help me extract the date and time
of the file.
The format of this is: yyyymmddhhmmss.
Example:
20100430070935 (April 30 2010 07:09:35)
How can i subtract the acquired time from system's time..??
The answer... (6 Replies)
Hello
I am using a ksh shell on solaris 9.
I am looking for a way to subtract two files and get a number
The first file contains only lines
LINE_A
LINE_B
LINE_C
The second file contain one number, the number of the line
Example
1
So the idea is to... (1 Reply)
Hi Guru's
i have a file which contains data as below(file.txt) and an inital value 8725
403
352
462
359
317
347
414
285
308
350
300
305
381
319
373
358 (11 Replies)
Hello all .
I have two arrays.
${ARRAY_MOUNT_POINT_CAPACITY}
${ARRAY_MOUNT_POINT_CAPACITY}.
Whats the synatx of subtracting their values , placing them in variable V1 and then echoeing it ???
Ive tried expr and let ...gives me ./test_code.sh: difference: bad number (3 Replies)
I have dates as follows in a file
20121029135649
20121029135721
20121030091540
20121030093420
20121030094340
20121030095427
20121030095856
20121030100104
20121030100251
All these dates are in sorted order. I need to find out the difference between the dates as follows
2nd row... (6 Replies)
Hello All,
I am a newbie to unix shell scripting and need to write a script that displays the difference between two variables that stores date value.
For example,
F1=`ls -ltr file1* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F2=`ls -ltr file2* | tail -1 |tr -s ' ' |cut -d' ' -f6,7,8`
F1... (3 Replies)
Discussion started by: priyaa2010
3 Replies
LEARN ABOUT OPENSOLARIS
cal
cal(1) User Commands cal(1)NAME
cal - display a calendar
SYNOPSIS
cal [ [month] year]
DESCRIPTION
The cal utility writes a Gregorian calendar to standard output. If the year operand is specified, a calendar for that year is written. If
no operands are specified, a calendar for the current month is written.
OPERANDS
The following operands are supported:
month Specify the month to be displayed, represented as a decimal integer from 1 (January) to 12 (December). The default is the current
month.
year Specify the year for which the calendar is displayed, represented as a decimal integer from 1 to 9999. The default is the current
year.
ENVIRONMENT VARIABLES
See environ(5) for descriptions of the following environment variables that affect the execution of cal: LANG, LC_ALL, LC_CTYPE, LC_TIME,
LC_MESSAGES, and NLSPATH.
TZ Determine the timezone used to calculate the value of the current month.
EXIT STATUS
The following exit values are returned:
0 Successful completion.
>0 An error occurred.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWesu |
+-----------------------------+-----------------------------+
|Interface Stability |Standard |
+-----------------------------+-----------------------------+
SEE ALSO calendar(1), attributes(5), environ(5), standards(5)NOTES
An unusual calendar is printed for September 1752. That is the month 11 days were skipped to make up for lack of leap year adjustments. To
see this calendar, type:
cal 9 1752
The command cal 83 refers to the year 83, not 1983.
The year is always considered to start in January.
SunOS 5.11 1 Feb 1995 cal(1)