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Top Forums Shell Programming and Scripting Replace everything but pattern in a line using sed Post 302619627 by Scrutinizer on Thursday 5th of April 2012 08:48:45 PM
Old 04-05-2012
You are not per chance only interested in the patterns themselves or do they need to remain on their original lines? Otherwise if your system has grep -o you can do this:
Code:
grep -Eo 'AB:[0-9]{9}' infile

and if you system does not have grep -o, you could do this:

Code:
sed 's/AB:[0-9]\{9\}/\n&\n/g' infile | grep -E 'AB:[0-9]{9}'

or for older sed:
Code:
sed 's/AB:[0-9]\{9\}/\
&\
/g' infile | grep -E 'AB:[0-9]{9}'

 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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