I think you have a cut and paste issue with your sample data. Going on what I believe you meant, this will read two lines from stdin and output the 'words' from each line using the indicated bit masking:

Code:

#!/usr/bin/env ksh


l=0
while read word
do
    if (( l < 1 ))
    then
        printf "%08x %d %d\n" 0x$word $(( 0x$word >> 9 )) $(( 0x$word & 0x1ffff ))
    else
        printf "%08x %d %d %d %d %d %d\n"  0x$word $(( 0x$word >> 14 )) $(( (0x$word >> 6)  & 0xff)) $(( (0x$word >> 3)  & 0x07)) $(( (0x$word >> 2)  & 0x01)) $(( (0x$word >> 1)  & 0x01)) $(( 0x$word & 0x01 ))
        break
    fi

    l=1
done

---------- Post updated at 21:07 ---------- Previous update was at 21:03 ----------

From your original post:

Shouldn't the two values in the file have been

Code:

000001ac
f7c392ac

given the output you listed, or the output should have been:

Code:

000001ac 0 428
ca85210e 207380 132 1 1 1 0

---------- Post updated at 21:16 ---------- Previous update was at 21:07 ----------

And one more note about the solution I posted. I originally read into word and assigned 0x to the variable so that I wouldn't need to prefix $word in each expression. This resulted in interesting behaviour in ksh -- bash seemed to get it right both ways. I need to test with a current build of ksh -- the most recent build I have access to here is 2011/02.

Code that has issues in Kshell:

Code:

#!/usr/bin/env ksh
l=0
while read word
do
    word="0x$word"
    if (( l < 1 ))
    then
        printf "%08x %d %d\n" $word $(( $word >> 9 )) $(( $word & 0x1ffff ))
    else
        printf "%08x %d %d %d %d %d %d\n"  $word $(( $word >> 14 )) $(( ($word >> 6)  & 0xff)) $(( ($word >> 3)  & 0x07)) $(( ($word >> 2)  & 0x01)) $(( ($word >> 1)  & 0x01)) $(( $word & 0x01 ))
        break
    fi

    l=1
done

It prints the first output line incorrectly, but the second is correct. Don't know if anybody wants to verify or offer an explanation, but it would be appreciated.