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Full Discussion: Use Webpage to Start Script
Top Forums Shell Programming and Scripting Use Webpage to Start Script Post 302618979 by JoeGazz84 on Thursday 5th of April 2012 03:24:02 PM
Old 04-05-2012
Quote:
Originally Posted by Corona688
The button and the code will actually be different pages, because when you click the button, that loads a separate, independent webpage, see? Each time you interact with CGI, it's a fresh page. The only things which come with it are things you put in every time.

Have your form load a PHP page with this in it:
Code:
<?php system("nohup /home/bots/rcbot.pl & disown"); ?>

I'm sorry, I guess I need to add two more things I forgot...

I need user "bots" to run this (password auth is off, have to use key for authentication), and if possible, it should check to see if the file/bot is already running and if it is, either return an error or kill the process. Is this possible to add to that code that was provided?

---------- Post updated 04-05-12 at 03:24 PM ---------- Previous update was 04-04-12 at 04:31 PM ----------

Is anyone able to help now that I've given a few more specifics? I'm not quite sure how to do this, thanks!
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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