Hi ,
I am using SUN OS Version 5.6.
I have a file that contains records of length 270. when I do 'set nu' in vi editor, I get the count as 86. whereas when I do "wc -l" on the command prompt, it shows the count as only 85. this is very strange. why would the 'wc' show 1 record less. The job... (3 Replies)
Hi all, I am trying to write a command that can help me count the number of lines in the /etc/passwd file ending in bash.
I have read through other threads but am yet to find one indicating how to locate a specifc word at the end of a line. I know i will need to use the wc command but when i... (8 Replies)
Hi friends, I am working on a perl script to count the commented lines, blank lines and source lines separately. Let me know if you have one. For example i have a file containing the lines:
/**
* SOURCE CODE
*/
public class SessionConstants {
/**
* Code for Session created
*/... (4 Replies)
how to count the total number of lines of all the files under a directory using perl script..
I mean if I have 10 files under a directory then I want to count the total number of lines of all the 10 files contain. Please help me in writing a perl script on this. (5 Replies)
Hi,
from the manual
listen(2): listen for connections on socket - Linux man page
It has a parameter called backlog and it limits the maximum length of queue of pending list.
If I set backlog to 128, is it means no more than 128 packets can be handled by server?
If I have three... (3 Replies)
Hi,
I am having .csv files contains some row -
Info: Value of field name 'SecurityExchange' is not supported ","Original Order Tuple
Please see the below perl code carefully-
/Info: (+),Original (\w+) Tuple/ and do {
($category, $type) = ($1, $2);
if($type eq 'Execution')... (1 Reply)
can i get a simple script for , Count same word which has come many times in single lines & pars
Eg file would be ==
"Thanks heman thanks thanks
Thanks heman
thanks man"
So resullt should be
Thanks = 5
heman=2
man = 1
thanks in advance :)
Please use code tags for code and... (1 Reply)
I am trying to figure out to find word count of each word from my file
sample file
hi how are you
hi are you ok
sample out put
hi 1
how 1
are 1
you 1
hi 1
are 1
you 1
ok 1
wc -l filename is not helping , i think we will have to split the lines and count and then print and also... (4 Replies)
Discussion started by: mirwasim
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)