03-24-2012
Hi I'm sorry again, I have come across another problem with the computation of the mean for my data. On top of having entire rows equal null values (NaN), the data has also entire rows with valid values equal to 0 and so I'm having fatal error on division by zero. How to revise the code such that if entire row has values of NaN and zero, it will print NaN and 0, respectively.
Many many thanks.
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LEARN ABOUT MOJAVE
casinh
CASINH(3) BSD Library Functions Manual CASINH(3)
NAME
casinh -- complex inverse hyperbolic sine function
SYNOPSIS
double complex
casinh(double complex z);
long double complex
casinhl(long double complex z);
float complex
casinhf(float complex z);
DESCRIPTION
casinh(z) computes the inverse hyperbolic sine of the complex floating-point number z, with branch cuts outside the interval [-i, i] along
the imaginary axis.
casinh() returns values in a strip of the complex plane with imaginary part in the interval [-Pi/2, Pi/2].
For all complex floating point numbers z,
casinh(conj(z)) = conj(casinh(z)).
casinh(-z) = -casinh(z)
SPECIAL VALUES
The symmetries of casinh() are used to abbreviate the specification of special values.
casinh(0 + 0i) returns 0 + 0 i.
casinh(x + inf i) returns inf + Pi/2 i, for finite positive-signed x.
casinh(x + NaN i) returns NaN + NaN i, for finite x.
casinh(inf + yi) returns inf + 0i, for finite positive-signed y.
casinh(inf + inf i) returns inf + Pi/4 i.
casinh(inf + NaN i) returns inf + NaN i.
casinh(NaN + 0i) returns NaN + 0i.
casinh(NaN + yi) returns NaN + NaN i, for finite y.
casinh(NaN + inf i) returns inf + NaN i.
casinh(NaN + NaN i) returns NaN + NaN i.
NOTES
SEE ALSO
csinh(3) complex(3)
STANDARDS
The casinh() function conforms to ISO/IEC 9899:2011.
4th Berkeley Distribution December 11, 2006 4th Berkeley Distribution