I'm having an issue when I export within my program. I'm getting the variable name, not the variable value. I have a configuration file (config.txt) that has the values of the variables set as so:
set -a
export ARCHIVEPOSourceDir="/interfaces/po/log /interfaces/po/data"
export... (2 Replies)
Hi,
i know that this topic discussed for many times but although i had researched them i couldnt succeed in my problem.
i am following a step-by-step instruction guide and must do the following:
-------------
To ensure access, set the path PATH $ORACLE_HOME/perl/bin:$PATH and set the Perl... (2 Replies)
okay, this shouldn't be difficult but I can't figure it out. How can I set a variable with another variable. I have the following:
foreach pe ($dir $sp)
set tpe = `echo $pe | grep M`
if ($tpe == M) then
set ${$pe} = M <--- This doesn't work
else
endif
end
In this case what... (2 Replies)
need a script that goes something like this
#!/usr/bin/bash
echo "input up to TEN values, separated by spaces"
read vari1 vari2 vari3 vari4 vari5 vari6 vari7 vari8 vari9 vari10
#set null variables to 9999 (somehow?)
#now echo all variables
echo $vari1 $vari2 $vari3 $vari4 $vari5 $vari6... (1 Reply)
I have a variable called PATH that contains a path
example: /Users/rtipton/Desktop/testusers/test
I need a sed command to set a variable called USER to the last directory name in that path
PATH="/Users/rtipton/Desktop/testusers/test"
and from that PATH i need USER to = test
I know sed... (4 Replies)
Can I use the read command to read the contents of a variable? I'm trying by using the following code and getting nothing back. I'm in a Linux environment.
#!/bin/ksh
IFS=~
VAR1=1~2~3~4
echo $VAR1 | read a b c d
print "$a $b $c $d" (9 Replies)
hi,
i'm not a root user and i want to know which user and in which file is loaded a variable seen in the "env" display ?
I will use this variable but i want to be sure that it will be a permanent variable !
i don't see it in my files (.profile , kshrc...) and neither in /etc/profile.
... (3 Replies)
greetings,
i have a variable $input that i want to use to set $output. $input is /dir/filename.mph and $input is passed to my script that i manipulate it as follows:
input=`basename $input`i want the $output to be filename_solved.mph, basically stuffing "_solved" in the filename. here's how i... (2 Replies)
Hello,
I created the following (snippet from larger code):
echo -n "A1: "
read A1
VERIFY=$(echo -n $A1|wc -c)
if ; then
echo -e "TOO MANY CHARACTERS"
fi
echo -n "A2: "
read A2
echo -n "A3: "
read A3
echo -e "Concat: $B1/$B2/$B3"
Basically what it does is it... (4 Replies)
Discussion started by: jl487
4 Replies
LEARN ABOUT LINUX
zegrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)