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Top Forums Shell Programming and Scripting /usr/local/bin/expr function not working Post 302607672 by sdosanjh on Thursday 15th of March 2012 05:00:34 AM
Old 03-15-2012
/usr/local/bin/expr function not working

Legends,

I am not able to set "expr" function in ksh script.
Below is the sample code i used, and output is as "Syntax error"
Please help me to come out of it.


Quote:
DATE1="`date -u +%Y`"
DATE2="`date -u +%m%d`"
CurrentDate="$DATE1$DATE2"
print "CurrentDate = $CurrentDate"
cutoffdate=`/usr/local/bin/expr $CurrentDate - 3`
print "cutoffdate = $cutoffdate"
cat /tmp/loadDSdata.tmpl|while read BASENAME
do
Len=`/usr/local/bin/expr length $BASENAME`
Len=`/usr/local/bin/expr $Len + 2`
Len2=`/usr/local/bin/expr $Len + 7`

print "Len = $Len"
print "Len2 = $Len2"

OUTPUT

Quote:
CurrentDate = 20120315
cutoffdate = 20120312
expr: syntax error
expr: syntax error
expr: syntax error
Len =
Len2 =

Last edited by sdosanjh; 03-15-2012 at 06:07 AM..
 

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expr(1) 						      General Commands Manual							   expr(1)

Name
       expr - evaluate expressions

Syntax
       expr arg...

Description
       The arguments are taken as an expression.  After evaluation, the result is written on the standard output.  Each token of the expression is
       a separate argument.

       The operators and keywords are listed below.  The list is in order of increasing precedence, with equal precedence operators grouped.

       expr | expr	   Yields the first expr if it is neither null nor 0.  Otherwise yields the second expr.

       expr & expr	   Yields the first expr if neither expr is null or 0.	Otherwise yields 0.

       expr relop expr	   The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false.  The  comparison	is
			   numeric if both expr are integers, otherwise lexicographic.

       expr + expr
	    expr - expr
			   Yields addition or subtraction of the arguments.

       expr * expr
	    expr / expr
	    expr % expr
			   Yields multiplication, division, or remainder of the arguments.

       expr : expr	   The	matching  operator compares the string first argument with the regular expression second argument; regular expres-
			   sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the  first  argument.
			   Otherwise, the matching operator yields the number of characters matched ('0' on failure).

       ( expr ) 	   parentheses for grouping.

Examples
       The first example adds 1 to the Shell variable a:
       a=`expr $a + 1`
       The second example finds the file name part (least significant part) of the pathname stored in variable a,
       expr $a : '.*/(.*)' '|' $a
       Note the quoted Shell metacharacters.

Diagnostics
       The command returns the following exit codes:

       0    The expression is neither null nor '0'.

       1    The expression is null or '0'.

       2    The expression is invalid.

See Also
       ed(1), sh(1), test(1)

																	   expr(1)
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