Sponsored Content
Full Discussion: Max of Date DD-MM-YYYY 17:30
Top Forums Shell Programming and Scripting Max of Date DD-MM-YYYY 17:30 Post 302606987 by fpmurphy on Tuesday 13th of March 2012 09:40:23 AM
Old 03-13-2012
Using ksh93
Code:
#!/bin/ksh93

maxdiff=0
while IFS=',' read date1 date2
do
   diff=$(( $(printf "%(%s)T" "$date1") - $(printf "%(%s)T" "$date2") ))
   (( diff > maxdiff )) && maxdiff=$diff
done < infile

mins=$((maxdiff % (60 * 60) / 60))
hours=$((maxdiff / (60 * 60)))

printf "%02d:%02d\n" $hours $mins

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Date Vadidation in YYYY-MM-DD

Date Vadidation in YYYY-MM-DD Hi , Please, Help me in validating given date that is passed in arg as YYYY-MM-DD. It should cover check 1 <= DD <= 31 and 1 <= MM <= 12 for each mm check 1 <=DD<= {28,30,31} (depending) for someYYYY and MM== 02 check 1 <= dd <= 29 I the... (1 Reply)
Discussion started by: itsmehihihi
1 Replies

2. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
Discussion started by: stringzz
9 Replies

3. Shell Programming and Scripting

converting the date field from dd/mm/yyyy to yyyy/mm/dd

How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix my script will generate text file which have two fields one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
Discussion started by: pareshan
4 Replies

4. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Discussion started by: keyboarder
6 Replies

5. Shell Programming and Scripting

Converting date DD MM YYYY to DD MON YYYY

Hello, I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10) To extract the dates, I am using shell substrings, i.e.: read line ... (4 Replies)
Discussion started by: Adamm
4 Replies

6. Shell Programming and Scripting

Converting a date to friday date and finding Min/Max date

Dear all, I have 2 questions. I have a file with many rows which has date of the format YYYYMMDD. 1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too. 2. After converting the date to... (10 Replies)
Discussion started by: 2001.arun
10 Replies

7. Shell Programming and Scripting

Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012

Hi I have a problem with Date format in my code. 1st I am trying to convert today's date to yesterday's using YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'` And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
Discussion started by: nithinankam
3 Replies

8. UNIX for Dummies Questions & Answers

Epoch date to YYYY/MM/DD or MM/DD/YYYY

I've seen a lot of posts on this and have tried the following: echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";' But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY. I am using bash and don't know... (4 Replies)
Discussion started by: newbie2010
4 Replies

9. Shell Programming and Scripting

Date Format MM/DD/YYYY

I am changing epoch times to dates. I was able to do the following: echo "$varx" | gawk '{print strftime("%c", $0)}' Mon Dec 31 16:26:40 2012 This changes the epoch date (which is what varx is) into localtime. However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
Discussion started by: newbie2010
2 Replies

10. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file... (3 Replies)
Discussion started by: Roozo
3 Replies
DATETIMEIMMUTABLE.DIFF(3)						 1						 DATETIMEIMMUTABLE.DIFF(3)

DateTime::diff - Returns the difference between two DateTime objects

       Object oriented style

SYNOPSIS
public DateInterval DateTime::diff (DateTimeInterface $datetime2, [bool $absolute = false]) DESCRIPTION
DateInterval DateTimeImmutable::diff (DateTimeInterface $datetime2, [bool $absolute = false]) DateInterval DateTimeInterface::diff (Date- TimeInterface $datetime2, [bool $absolute = false]) Procedural style DateInterval date_diff (DateTimeInterface $datetime1, DateTimeInterface $datetime2, [bool $absolute = false]) Returns the difference between two DateTimeInterface objects. PARAMETERS
o $datetime - The date to compare to. o $absolute - Should the interval be forced to be positive? RETURN VALUES
The DateInterval object representing the difference between the two dates or FALSE on failure. EXAMPLES
Example #1 DateTimeImmutable.diff(3) example Object oriented style <?php $datetime1 = new DateTime('2009-10-11'); $datetime2 = new DateTime('2009-10-13'); $interval = $datetime1->diff($datetime2); echo $interval->format('%R%a days'); ?> Procedural style <?php $datetime1 = date_create('2009-10-11'); $datetime2 = date_create('2009-10-13'); $interval = date_diff($datetime1, $datetime2); echo $interval->format('%R%a days'); ?> The above examples will output: +2 days Example #2 DateTime object comparison Note As of PHP 5.2.2, DateTime objects can be compared using comparison operators. <?php $date1 = new DateTime("now"); $date2 = new DateTime("tomorrow"); var_dump($date1 == $date2); var_dump($date1 < $date2); var_dump($date1 > $date2); ?> The above example will output: bool(false) bool(true) bool(false) SEE ALSO
DateInterval.format(3), DateTime.add(3), DateTime.sub(3). PHP Documentation Group DATETIMEIMMUTABLE.DIFF(3)
All times are GMT -4. The time now is 05:18 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy