Date Vadidation in YYYY-MM-DD
Hi ,
Please, Help me in validating given date that is passed in arg as YYYY-MM-DD.
It should cover
check 1 <= DD <= 31 and 1 <= MM <= 12
for each mm check 1 <=DD<= {28,30,31} (depending)
for someYYYY and MM== 02 check 1 <= dd <= 29
I the... (1 Reply)
I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Dear all,
I have 2 questions.
I have a file with many rows which has date of the format YYYYMMDD.
1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too.
2. After converting the date to... (10 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am changing epoch times to dates. I was able to do the following:
echo "$varx" | gawk '{print strftime("%c", $0)}'
Mon Dec 31 16:26:40 2012
This changes the epoch date (which is what varx is) into localtime.
However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
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curl_global_cleanup
curl_global_cleanup(3) libcurl Manual curl_global_cleanup(3)NAME
curl_global_cleanup - global libcurl cleanup
SYNOPSIS
#include <curl/curl.h>
void curl_global_cleanup(void);
DESCRIPTION
This function releases resources acquired by curl_global_init(3).
You should call curl_global_cleanup(3) once for each call you make to curl_global_init(3), after you are done using libcurl.
This function is not thread safe. You must not call it when any other thread in the program (i.e. a thread sharing the same memory) is run-
ning. This doesn't just mean no other thread that is using libcurl. Because curl_global_cleanup(3) calls functions of other libraries
that are similarly thread unsafe, it could conflict with any other thread that uses these other libraries.
See the description in libcurl(3) of global environment requirements for details of how to use this function.
SEE ALSO curl_global_init(3), libcurl(3),
libcurl 7.8 17 Feb 2006 curl_global_cleanup(3)