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Top Forums Shell Programming and Scripting Script to upload latest file to other server via FTP Post 302605138 by Corona688 on Tuesday 6th of March 2012 05:12:55 PM
Old 03-06-2012
Quote:
Originally Posted by nbsparks
So I created a ".netrc" file in my home folder. Do I need to chmod it in any way?
chmod 600 it.

Quote:
Then, I'll create a new .SH script like this:
You removed a few too many newlines. Smilie

I doubt you actually want to upload these files into root, /filename. (Though you might have a chroot going on, for all I know.) Put them where you actually want them to go...

Code:
#!/bin/bash

( cd /home/mc/archive/sbhouse

find . -type f -mtime -1 | while read LINE
do
        echo "put $LINE /path/to/$LINE"
done

echo "quit" ) | ftp 192.168.0.10

Quote:
So would this copy the file to the ftproot of the minecraft user on the other server?
I know nothing of minecraft's internal organization, you've shown nothing of it, and you provided the find yourself. I honestly don't know if it does what you want, your requirements aren't clear.

Try replacing ftp 192.168.0.10 with cat, see what your program prints. Is it naming the files you want for upload?

Last edited by Corona688; 03-06-2012 at 06:18 PM..
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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