...
If it is date then append "<space>00:00:00" to it.
If it is a time stamp, store the data in a different file(invalid_dttmstmp.txt) and remove from this file.
If it is a date timestamp then do nothing.
Input file:
Expected output
...
Could someone tell me how to get the date/time (to the second) a file was last modified? I need to know if a file was modified in the last 30 seconds from the system date. I'm on AIX/unix 4.3 (3 Replies)
Hi All,
i have a time stamp. from that i am trying to awk to get the year, month and date.
TIME=20060614092446
DESIRED OUTPUT: 20060614
i am doing the following;
TIME=20060614092446
$ TimeStarted=`expr match '$TIME' '.*\(......\)'`
echo $TimeStarted
i am not getting... (2 Replies)
Hello all
This is a sample vmstat output ...
$ vmstat 2 2
kthr memory page disk faults cpu
r b w swap free re mf pi po fr de sr hx hx hx hx in sy cs us sy id
1 0 0 23105784 7810488 323 767 1742 5 5 0 0 0 0 0 0 683 780 457 43 ... (9 Replies)
Hi,
This is my script:
#! /usr/bin/ksh
cd /app/chdata/workflow/suppl/esoutput/spd/testing
for file in /app/chdata/workflow/suppl/esoutput/spd/testing
do
sort *.txt | awk '{ file=substr($0,1,2)".txt"; print >> file }' ... (3 Replies)
Hi,
I have list of files as below, with prefix named as date & time. Anyone how to transform each file as below to yyyy-mm-dd hh:mm:ss
Regards, (8 Replies)
Hi,
I have a file containing timestamp( Example given below). How can i get date(mmd-dd-yyyy) from it?
($> cat file1.txt
2008-11-24 05:17:00.7043)
Thanks,
Sri (2 Replies)
How would I convert a unix timestamp such as "1232144092" to a readable date such as "1/16/2009 10:14:28 PM" ?
I thought I could use date, but I don't think so now.. Any help would be great!! (4 Replies)
Hi,
I have a file file1 having data as below
20110501,070742, ,012345678909,09999999999,68.5,
20110501,070236, ,089375855455,09376383333,374.3,
20110501,070525, ,090345895555,08444233444,206.2,
20110501,230051, ,000934744433,07624262223,480.1,
First field is date(YYYYMMDD) and second... (5 Replies)
Hi,
I have many files in the source directory but I need to process with the latest timestamp file.
I am using linux operating system. i want extract the file created timestamp( Ext_File_create_date=)
With this format YYYYMMDD-
i have searched the relevent command in the unix forms but did... (5 Replies)
Hello,
I have files that with a naming convention as shown below. Some of the files have dates in the file name and some of them don't have dates in the file name.
imap-hp-import-20150917.txt
imap-dell-gec-import-20150901.txt
imap-cvs-import-20150915.txt
imap-gec-import.txt... (8 Replies)
Discussion started by: Saanvi1
8 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)