i want to get a substring from a string and used such shell script:
var_year=`expr substr "07132006" 5 4`
echo $var_year
but i got such error message: expr: syntax error. why?
Note: Kshell used on solaris 8. :confused: (5 Replies)
I found below script to check whether the variable is a digit in ksh.
############################
#!/bin/ksh
REPLY="3f"
if ]*\)'` != ${REPLY} && "${REPLY}" != "0" ]]
then
print "is digit\n"
else
print "not digit\n"
fi
############################
Although it works fine, but... (6 Replies)
I am trying to run the script bellow but its given me "syntax error at line 20 :'done' unexpected." error message"
can someone check to see if the script is ok? and correct me pls.
Today is my first day with scripting.
Gurus should pls help out
#!/bin/ksh
# Purpose: Check to see if file... (3 Replies)
I know I asked a similar question but I want to know if there is a regular expression existing that with a korn shell cmd, finds any timestamp data records in a file where it is greater then a timestamp in a shell variable ?
something like :
grep all records where it has a timestamp >... (5 Replies)
Hi Guys,
THis is the first time am using the expr expression.
I like to know how to write the expression a=(b\100)*a.
THis works fine if it gives without a bracket. the bracket should be present as i wanted to define the order of execution.
Help me out.
Thanks for your help in advance.... (2 Replies)
hello to everyone,
i am writing a shell script in unix and i use the following command:
lnum= cut -f 1 -d : aa
passline=`expr $lnum + 1`
echo "$passline"
with the following command i get the value that is stored in the first field of the file "aa" and i save it in the variable "lnum". i am... (2 Replies)
Hi All,
This is a piece of code from one of my scripts:
t1=`cat temp3.21447 | grep WEALTHTOUC_TRANS_20100409_233127.txt.txt.TRG | awk '{print $3}' | cut -c1-5`
t2=`cat temp3.21447 | grep WEALTHTOUC_TRANS_20100409_233127.txt.txt.TRG | awk '{print $5}' | cut -c1-5`
#t1=23:43... (5 Replies)
Hi All,
As per my knowledge in unix, my code looks fine. But still I am getting error (expr:syntax error). Please help me to resolve this error.
Script :
PRE_LBNO=0
PRE_DATE=0
TOT_PAY=0
TOT_REM=0
TOTAL=1
for Record_Type in `cut -c 1 Inputt.dat`
do
if ;
then
CURR_LBNO=` cut -c... (6 Replies)
This really puzzles me. The following code gives me the error 'expr: syntax error' when I try to do multi-line comment using here document
<<EOF
echo "Sum is: `expr $1 + $2`"
EOF
Even if I explicitly comment out the line containing the expr using "#", the error message would still exist... (3 Replies)
Hi,
I tried to look up the issue i'm experiencing, but i'm confused what's wrong with my script.
After executing the script I'm getting the following error
expr: non-numeric argument
syntax error on line 1, teletype
After some research, it seems that the problem relates to bc.
I have... (1 Reply)
Discussion started by: nms
1 Replies
LEARN ABOUT BSD
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
7th Edition April 29, 1985 EXPR(1)