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Top Forums Shell Programming and Scripting Help with awk script and update position Post 302598739 by say170 on Wednesday 15th of February 2012 09:50:41 AM
Old 02-15-2012
Help with awk script and update position

Hi, I'm using AIX 5.3 and am trying to get this to work as I need:

Code:
echo 6078:  6072  6073  6074  6075  6076  6077  6078  6079 | awk '{n=$8} n{sub(n,n+1000000)}1'
1006078: 6072 6073 6074 6075 6076 6077 6078 6079

I only want it to change second occurance of 6078 (ie $8) and not the first ($1).
I tried:

Code:
echo 6078:  6072  6073  6074  6075  6076  6077  6078  6079 | awk '{n=" "$8" "} n{sub(n," "n+1000000" ")}1'
6078: 6072 6073 6074 6075 6076 6077 1006078 6079

but I'm running piping through 10 awks (one to change each number), but on the rows with less than 10, it goes haywire if I have the " " in.
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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