Sponsored Content
Full Discussion: Colon in awk script output
Top Forums Shell Programming and Scripting Colon in awk script output Post 302598137 by alister on Monday 13th of February 2012 01:27:10 PM
Old 02-13-2012
Code:
$  echo 1234: 1234 123 123 444 555 666 7777  | awk '{$1=$1+10000000":"}1'
10001234: 1234 123 123 444 555 666 7777

Regards,
Alister
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

script the output with awk

Please i need your help. i made this script with awk, this scripts count and list a pattern for each directory in the output as shown. but not as desired. i want the output will be listed in a tabular way, using awk: cuenta_cdrs() { for dir in * do cd $dir for file in * do ... (4 Replies)
Discussion started by: alexcol
4 Replies

2. UNIX for Dummies Questions & Answers

Multiple field separators in awk? (First a space, then a colon)

How do I deal with extracting a portion of a record when multiple field separators are involved. Let's say I have: Mike Harrington;(555) 555-5555:250:100:175 Christian Dobbins;(555) 555-2358:155:90:201 Susan Dalsass;(555) 555-6279:250:60:50 Archie McNichol;(555) 555-1348:250:100:175 Jody... (3 Replies)
Discussion started by: doubleminus
3 Replies

3. Shell Programming and Scripting

Script required to put colon

Hi Expert, I need help on script to put colon between two characters. From this line 60060160B18414009C557D9DE02CDF11 to this 60:06:01:60:B1:84:14:00:9C:55:7D:9D:E0:2C:DF:11 Any way to make it on script. (2 Replies)
Discussion started by: ranjancom2000
2 Replies

4. AIX

AIX HMC - Getting Colon ":" in output

Hi, I am executing below commands on HMC. I see that there is only colon ":" in output. Can someone please help why I am getting ":" in output? Why I am not getting proper output? xxxxx@yyyyhmc1:~> viosvrcmd -m PCC-p590#2-SN024D8F0 -p ppvio1 -c "lsmap -all" :xxxxx@yyyyhmc1:~> viosvrcmd... (0 Replies)
Discussion started by: marya
0 Replies

5. Shell Programming and Scripting

Awk script to run a sql and print the output to an output file

Hi All, I have around 900 Select Sql's which I would like to run in an awk script and print the output of those sql's in an txt file. Can you anyone pls let me know how do I do it and execute the awk script? Thanks. (4 Replies)
Discussion started by: adept
4 Replies

6. Shell Programming and Scripting

awk :help to parse a file to change to separated by colon ":"

Hi experts , I am trying to get the below output: file : 0/6/4/1 0x0019503C2E26 5 UP lan5 snap5 1 ETHER Yes 224 0/6/4/0 0x0019503C2E25 6 UP lan6 snap6 2 ETHER Yes 224 0/2/1/0 0x0019503E6900 0 UP lan0 snap0 3 ETHER Yes 224... (8 Replies)
Discussion started by: rveri
8 Replies

7. UNIX for Dummies Questions & Answers

awk colon separated items

Hi, I need to filter my data based on items in column 23. Column 1 until column 23 are tab separated. This is how column 23 looks like: PRIMARY=<0/1:504:499,5:.:.:.:0.01:1:15:.> I want to extract lines if items 7 (separated by : ) in column 23 are more than 0.25 . In example above , item... (2 Replies)
Discussion started by: janshamsani
2 Replies

8. Shell Programming and Scripting

awk does not find ids with semi-colon in the name

I am using awk to search $5 of the "input" file using the "list" file as the search criteria. So if the id in line 1 of "list" is found in "search" then it is counted in the ids found. However, if the line in "list" is not found in "search", then it is outputted as is missing. The awk below runs... (3 Replies)
Discussion started by: cmccabe
3 Replies

9. Shell Programming and Scripting

awk unique count of partial match with semi-colon

Trying to get the unique count of the below input, but if the text in beginning of $5 is a partial match to another line in the file then it is not unique. awk awk '!seen++ {n++} END {print n}' input 7 input chr1 159174749 159174770 chr1:159174749-159174770 ACKR1 chr1 ... (2 Replies)
Discussion started by: cmccabe
2 Replies

10. UNIX for Beginners Questions & Answers

Shell script to call and sort awk script and output

I'm trying to create a shell script that takes a awk script that I wrote and a filename as an argument. I was able to get that done but I'm having trouble figuring out how to keep the header of the output at the top but sort the rest of the rows alphabetically. This is what I have now but it is... (1 Reply)
Discussion started by: Eric7giants
1 Replies
RLM_DBM_PARSE(8)					      System Manager's Manual						  RLM_DBM_PARSE(8)

NAME
rlm_dbm_parse - transforms simple syntax into rlm_dbm format SYNOPSIS
rlm_dbm_parse [-c] [-d raddb] [-i inputfile] [-o outputfile] [-x] [-v] [-q] [username ...] DESCRIPTION
rlm_dbm_parse reads a file of the syntax defined below, and writes a database file usable by rlm_dbm or edits current database. INPUT FORMAT
rlm_dbm_parse reads a format similar to the one used by the files module. In incomplete RFC2234 ABNF, it looks like this: entries = *entry entry = identifier TAB definition identifier = username / group-name username = +PCHAR groupname = +PCHAR definition = (check-item ",")* LF ( *( reply-item ",") / ";" ) LF check-item = AS IN FILES reply-item = AS IN FILES * need definition of username and groupname As an example, these are the standard files definitions (files module). DEFAULT Service-Type == Framed-User Framed-IP-Address = 255.255.255.254, Framed-MTU = 576, Service-Type = Framed-User, Fall-Through = Yes #except who call from number 555-666 DEFAULT Auth-Type := Reject,Service-Type ==Framed-User, Calling-Station-ID == "555-666" #or call number 555-667 DEFAULT Auth-Type := Reject,Service-Type ==Framed-User, Calling-Station-ID == "555-667" To be a valid rlm_dbm input file, it should look like this: DEFAULT Service-Type == Framed-User # (1) Framed-IP-Address = 255.255.255.254, # comma, list cont'd Framed-MTU = 576, Service-Type = Framed-User, Fall-Through = Yes # , end of list Auth-Type := Reject,Service-Type ==Framed-User, # (2) Calling-Station-ID == "555-666" ; # ;, no reply items Auth-Type := Reject,Service-Type ==Framed-User, # (3) Calling-Station-ID == "555-667" ; # ditto This user (the DEFAULT user) contains three entries, 1, 2 and 3. The first entry has a list of reply items, terminated by a reply item without a trailing comma. Entries 2 and 3 has empty reply lists, as indicated by the semicolon. This is necessary to separate an empty line (which is ignored) from the empty list. Definition Fall-Through = Yes used in order to say module to check next record. By default Fall- Through = Yes. OPTIONS
-d raddb Use raddb as the radiusd configuration directory. -i inputfile Use file as the input file. If not defined then use standard input. -o outputfile Use file as the output file. -c Create a new database (empty output file before writing) -x Enable debug mode. Multiple x flags increase debug level. -q Do not print statistics (quiet). -v Print the version and exit. -r Remove a username or group name from the database. SEE ALSO
radiusd(8) AUTHORS
Author: Andrei Koulik <rlm_dbm@agk.nnov.ru> Documentation: Bjorn Nordbo <bn@nextra.com> RLM_DBM_PARSE(8)
All times are GMT -4. The time now is 04:03 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy