i read the variable ph from file and i wanna to print it in awk.
example
ph=`cat tmpbatch`
tail h.txt|grep "| |"|awk -F"|" '{ print "@unpdx.sql",$5 }'"$ph"
i try this but it does not work (8 Replies)
How can I pass the name of the variable inside a for statment
I have a script something like below:
classA=12
classB=14
classC=16
# classD = 20
all_class="classA classB classC"
for i in $all_class
do
echo $i = $($i) #<---- this one not work
#echo $i = $(echo $i) ... (1 Reply)
Hi,
Could any one please let me know what is the option
available in UNIX to print by specifying the paper size?
We are using Unix11i. I could n't see any option specified in the 'lp' command to print the report by specifying the size of the paper. It would be of great help to me, if... (1 Reply)
:b:Hi All,
I have a part of a script below:
var1="value1"
awk 'BEGIN {printf("%36s \n ","value1")}'
Instead of directly giving the "value1" , I need to give using "var1" in the above awk statement.
Is this possible?
If so, what is the modified awk command?
Thanks in advance
JS (1 Reply)
Let's say I want to print the arguments $4 till $#, how can I do this?
$# contains the number of arguments
$@ contain all the arguments as string
What i need is something like
for i in $4_till_$#; do
#do something with $i
convert $i ~/$output
done
The first 3 arguments are used as options... (6 Replies)
I have list of files:
ls
a.pdf
b.pdf
c.pdf
and so on...
and I have a file like this:
cat file1
apple
mango
pear
and so on...
I want to rename my file like this: (7 Replies)
Hi,
I've stored the output of a command into a variable.
The variable contains the following output:
outputline1 outputline2 outputline3 ...
How can I echo the variable so that the output is as follow and not one line:
outputline1
outputline2
outputline2
...
Thanks a lot! (4 Replies)
hey,
just want to ask how to do this.
ex.
g="hi i am john"
h=`echo $g | awk '{print $2}'`
echo $h
OUTPUT is 'i'
What if I want to use a variable instead of using '2', how do I do that?
Because this one does not work:
a=2
h=`echo $g | awk '{print ${$a}}'`
this one also does not... (3 Replies)
i have this variable:
varT="1--2--3--5"
i want to use awk to print field 3 from this variable. i dont want to do the "echo $varT".
but here's my awk code:
awk -v valA="$varT" "BEGIN {print valA}"
this prints the entire line. i feel like i'm so close to getting what i want. i... (4 Replies)
Hi guys,
I have a file "abc.dat" in below format:
FILE_PATH||||$F_PATH
TABLE_LIST||||a|b|c
SYST_NM||||${SRC_SYST}
Now I am trying to read the above file and want to print the value for above dollar variables F_PATH and SRC_SYST. The problem is it's reading the dollar variables as... (5 Replies)
Discussion started by: abcabc1103
5 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)