01-20-2012
Thanks for the reply. But your solution does not do what I need. My problem is more general. In my problem the var1 and var2 are not literal strings but are themselves arbitrary and need to have the text before them stripped away. Here is a clearer description of what I need
Toby> cat sample1
This is some arbitrary text before var1, This IS SOME DIFFERENT ARBITRARY TEXT before var2
This is another line with first part before item1, This is the second part before item2
Toby> sed 's/.*\(var1\).*\(var2\)/\1, \2/g' sample1
var1, var2
This is another line with first part before item1, This is the second part before item2
The output I need from sed would then be
var1, var2
item1, item2
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
MSG="THERE WERE XX RECORDS IN ERROR TABLE,AAAA, WHEN LOADING THE BBBB TABLE WITH EXTRACT FROM CCCC INTO TABLES FOR , DATABASE DDDD."
echo "$MSG" > /tmp/mplanmsg.$$.out
I wan to replace XX with the content in $recordXX
cat /tmp/mplanmsg.$$.out|sed 's/XX/\$recordXX/g'| sed... (3 Replies)
Discussion started by: leemjesse
3 Replies
2. Shell Programming and Scripting
All,
I have the following file:
--------------------------------------
#
# /etc/pam.d/common-password - password-related modules common to all services
#
# This file is included from other service-specific PAM config files,
# and should contain a list of modules that define the services... (2 Replies)
Discussion started by: RobertBerrie
2 Replies
3. Shell Programming and Scripting
Unfortunately this chap has been banned for some reason and I was looking forward to the resolution of his question: -
https://www.unix.com/shell-programming-scripting/123118-append-position-28-33-a.html
He was asking if you can use sed to match a pattern you want to replace within a... (6 Replies)
Discussion started by: steadyonabix
6 Replies
4. Shell Programming and Scripting
I found a sed example that works for me, however, now i would like to understand what it is doing:
$ echo "<b>foo </b >bar" | sed 's/<*>//g'
foo bar
the part that i don't understand is the *
my guess is that ^> means the first instance of > stop matching but why * and how is it able to... (2 Replies)
Discussion started by: adambot
2 Replies
5. Shell Programming and Scripting
Hello All,
I have the following lines in a file
<address location="test"
ConnectionName="test" />
I want to replace the above lines by
<address location="test123" />
I am usind SED and not able to remove the new line characters between the two lines.
Can anyone please help... (4 Replies)
Discussion started by: ramk
4 Replies
6. Shell Programming and Scripting
Hi
My log file is Testtmp2
cat Testtmp2
12:12:38
12:14:29
12:17:34
12:19:08
12:20:10
12:21:35
12:22:20
12:22:26
12:22:34
12:22:38
12:28:14
12:31:35
12:32:50
12:33:04 (3 Replies)
Discussion started by: rahkumar
3 Replies
7. Shell Programming and Scripting
'Hi
I'm using the following code to extract the lines(and redirect them to a txt file) after the pattern match. But the output is inclusive of the line with pattern match.
Which option is to be used to exclude the line containing the pattern?
sed -n '/Conn.*User/,$p' > consumers.txt (11 Replies)
Discussion started by: essem
11 Replies
8. Shell Programming and Scripting
Hi all,
Is Perl included by default in Ubuntu? I'm trying to write a program using as few languages as possible, and since I'm using a few Perl one-liners to do non-greedy matching, it's considered another language, and this is a bad thing.
Basically, I'm using a Perl one-liner to grab XML... (3 Replies)
Discussion started by: Zel2008
3 Replies
9. Programming
I've been having problems lately trying to do pattern matching in C while implementing wildcards. Take for instance the following code:
#include <sys/types.h>
#include <sys/stat.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <dirent.h>
#include <string.h> ... (14 Replies)
Discussion started by: Azrael
14 Replies
10. Shell Programming and Scripting
Hi,
I know how to replace a string with another in a file.
But, i wish to replace the below string pattern
EncryptedPassword="{gafgfa}]\asffafsf312a" i.e EncryptedPassword="<any random string>"
To
EncryptedPassword=""
i.e remove the random password to a empty string.
Can you... (3 Replies)
Discussion started by: mohtashims
3 Replies
LEARN ABOUT CENTOS
grub-render-label
GRUB-RENDER-LABEL(1) User Commands GRUB-RENDER-LABEL(1)
NAME
grub-render-label - generate a .disk_label for Apple Macs.
SYNOPSIS
grub-render-label [OPTION...] [OPTIONS]
DESCRIPTION
Render Apple .disk_label.
-b, --bgcolor=COLOR
use COLOR for background
-c, --color=COLOR
use COLOR for text
-f, --font=FILE
use FILE as font (PF2).
-i, --input=FILE
read text from FILE.
-o, --output=FILE
set output filename. Default is STDOUT
-t, --text=STRING
set the label to render
-v, --verbose
print verbose messages.
-?, --help
give this help list
--usage
give a short usage message
-V, --version
print program version
Mandatory or optional arguments to long options are also mandatory or optional for any corresponding short options.
REPORTING BUGS
Report bugs to <bug-grub@gnu.org>.
SEE ALSO
The full documentation for grub-render-label is maintained as a Texinfo manual. If the info and grub-render-label programs are properly
installed at your site, the command
info grub-render-label
should give you access to the complete manual.
grub-render-label (GRUB) 2.02-2ubuntu8.3 July 2018 GRUB-RENDER-LABEL(1)