With the if statement:
if
How can I make it so it accepts a wildcard after the ${CURR_DAY_MONTH} variable?
Putting
a -f /webtrends/SUN/mrw2/access.${CURR_DAY_DAY}${CURR_DAY_MONTH}*
won't work, right? I think I need some kind of special character so it knows the wildcard is... (3 Replies)
I have the following
--------------------
foreach var (STO SNY WKF)
set ta = 5
end
---------
How can I echo both variables at the same time. Something to the effect of
echo ${$var}ta
But this doesn't work. Seems like it would. Thanks. (4 Replies)
I am just wondering if it's possible to refer to variables within a sed statement as follows:-
cat $file | sed -e 1's/$oldtext/$newtext/' > $file
as when I run the script, the variables are not recognised and nothing happens..??
Thanks (5 Replies)
Ok, So up front I'm going to say that I'm a very elementary scripter, and I tend to use tools I don't fully understand, but I shotgun at something until I can get it to work...that said, I can't for the life of me understand why I can't get this to go down the way I want it to.
The goal:
-to... (6 Replies)
meas is a shell variable, and this works perfectly fine for me:
awk -v var=$meas -F, '$1==var' /abcd/efgh.txt > temp1.csv
However, i want to introduce another shell variable, named, defnfile in the statement, in place of hardcoded path for efgh.txt like:
awk -v var=$meas -F, '$1==var'... (3 Replies)
is it possible to call a variable in a case statement, for example
lsmonth=Jan|Feb
l |while read ans
do
mymonth=`echo $ans |awk '{print $6}'`
case $mymonth in
$lsmonth) echo do something
;;
*) echo do something else
;;
esac
done
I want to use $lsmonth... (8 Replies)
HI,
I have 5 variables var1, var2, var3, var4 and var5
I need to initialize all of them to zero.
Is there a way to do it in a single line
something like this
var1=var2=var3=var4=var5=0.
I am unable to achieve this.
What is going wrong? (2 Replies)
Environment:
BASH version: GNU bash, version 3.2.51(1)-release (sparc-sun-solaris2.10)
Copyright (C) 2007 Free Software Foundation, Inc.
OS: Oracle Solaris 10 9/10 s10s_u9wos_14a SPARC
Copyright (c) 2010, Oracle and/or its affiliates. All rights reserved.
... (4 Replies)
Hi folks,
I have a scenario to convert the update statements into insert statements using shell script (awk, sed...) or in database using regex.
I have a bunch of update statements with all columns in a file which I need to convert into insert statements.
UPDATE TABLE_A SET COL1=1 WHERE... (0 Replies)
Discussion started by: dev123
0 Replies
LEARN ABOUT OSX
colrm
COLRM(1) BSD General Commands Manual COLRM(1)NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO awk(1), column(1), cut(1), paste(1)HISTORY
The colrm command appeared in 3.0BSD.
BSD August 4, 2004 BSD