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Full Discussion: Removing string between two particular strings in a line
Top Forums Shell Programming and Scripting Removing string between two particular strings in a line Post 302587931 by ctsgnb on Friday 6th of January 2012 10:05:55 AM
Old 01-06-2012
Quote:
Originally Posted by mirni
You were close. Sed's pattern matching is greedy though, so the regex
Code:
s/\[.*\]//g

will match everything from the first opening bracket to the last closing one. What you need is to replace the '.' (which means 'any character'), with 'not closing bracket', that is [^]]:
Code:
sed 's/\[[^]]*\]//g'

should do the trick
In fact the last closing bracket does not need to be escaped, it will already be taken as litteral :
Code:
...  sed 's/\[[^]]*]//g'

---------- Post updated at 04:05 PM ---------- Previous update was at 03:56 PM ----------

The right expression to do it one shot is :

Code:
... sed 's/[[(][^])]*[])]//g'

Code:
$ echo 'this (is) a [test]!!!'
this (is) a [test]!!!
$ echo 'this (is) a [test]!!!' | sed 's/[[(][^])]*[])]//g'
this  a !!!

Note that this one shot notation will also match the [...) and (...] blocks :
Code:
$ echo 'this (is) a [darn) funny (and] crazy [test]!!!'
this (is) a [darn) funny (and] crazy [test]!!!
$ echo 'this (is) a [darn) funny (and] crazy [test]!!!' | sed 's/[[(][^])]*[])]//g'
this  a  funny  crazy !!!

Last edited by ctsgnb; 01-06-2012 at 11:11 AM..
This User Gave Thanks to ctsgnb For This Post:
ppatra
 

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