Hi,
I would like to display the following message from my shell (Korn) script
Copy "old_file.txt" to "new_file.txt"
My code looks as follows
print "Copy "old_file.txt" to "new_file.txt""
However, when I execute the script, I get the following output
Copy old_file.txt to... (6 Replies)
I'm using awk '{print $1}' and it works most of the time to print the contents of a mysql query loop, but occationally I get a field with some special character in it, is there a way to tell awk to ignore all special characters between my FS? I have >186K records, so building a list of ALL special... (6 Replies)
Hi, I wish to replace a new line with br (html) but it doesn't seem to work
message=$(echo ${FORM_message} | tr '\r' '<br \/>' )
what it gives me seems to be ... b...?
I am also having problem escaping hash sign in cut command:
list=$(echo "$line" | cut -d'\#;\#' -f1) ;
my intention is... (2 Replies)
Hi ,
I want to replace the special characters in the file.
For eg: cat abc
1234/4455/acb
234/k/lll/
234`fs`fd
I want to replace / and ` with the letter a and the output should like below. How to achieve this.
1234a4455aacb
234akallla
234afsafd (2 Replies)
Hello Everyone,
I need to read an encrypted password from the user and update that value in an xml file. I am trying to use "sed" for searching the appropriate tag and replacing this new value that get from the user. Since the encrypted password can contain special characters(like /,\,&,etc),... (4 Replies)
Need help in escaping special characters in sed command.
Here is the the string which i am trying to find a replace with
From :- REQUEST_TYPE=PIXEL&MSG_ID={//MESSAGE_ID}
To :- REQUEST_TYPE=PIXEL&MSG_ID= X_EDELIVERY_MESSAGE_ID & BATCH_ID= X_EDELIVERY_BATCH_ID
Here is the sed command i am... (2 Replies)
Hi Unix Guru,
I have an requirement for replace some specail characters in a file, my file came from mainframe.
please see below example:
when open it with vi
17896660|89059215|04/24/1998 00:00:00.000000| abc 123-453-1312^M<85>^M<85>|124557
if I run cat -v I got following:... (25 Replies)
Hi,
I have written a unix expect utility "ssh-login.exp" which connects (ssh) to remote host and execute some shell script. I am calling this "ssh-login.exp" utility from another shell script.
"ssh-login.exp" takes username, password, host and shell script path to execute on remote host. All... (1 Reply)
I have an application which I am integrating with that accepts the password via a CLI. I am running in to issues with passwords that contain special characters. I tried to escape them all, but I ran in to an issue where I cannot escape the characters
'
]
My attempt is as follows:
$... (2 Replies)
Hi Team,
I have data like this.
|*|.5|*|0.2|*|A.B|*|
Would like to add zero (0) before the decimal point where there is no zero as
|*|0.5|*|0.2|*|A.B|*|
How to replace |*|. with |*|0.
I tried below command which didn't work
echo '|*|.5|*|0.2|*|A.B|*' | sed... (4 Replies)
Discussion started by: Ravi.K
4 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)