Hi,
I am trying to redefine the value of a variable based on another variable value. And I want to read in my variables from a enviroment file in the end -- at least I think so. But 1st here's what I want I need to get working:
var_1="11 10 9 8 7 6 5 4 3 2 1"
var_2=3
var_3=4
So I want... (12 Replies)
Can anyone tell me what is the purpose of a substitute variable in the unix programming language and give an example where it may be used?
Thanks! (0 Replies)
hi all,
how do i assign values passed in from command line to and sql statement in perl ?? e.g
i want to assign :name1 and :Name2 to be whatever is passed into the perl script command line
my $sqlStr = "select * from test_table where column1 = upper(nvl(:name1, name1 )) and column2... (1 Reply)
hi all,
Assume that i a having the following three lines in an executable file
#/bin/bash
a=Tue
Tue=1
When i give echo $a the value should be 1, how to do this. Your suggestions please.
Thanks in advance,
Anish (4 Replies)
I have a large csv file that looks like this:
The 3rd field is a unix time stamp that I want to convert to human readable.
I wrote a bash script with this code:
IFS=$','
cat $1 | while read ID user DATE text flags read; do
echo -e "$ID,$user,$(date -d @$DATE),$text,$flags,$read... (3 Replies)
Hi There,
I am writing a ksh script which assigns variable values from file "A" and passes that variables to file "B". While passing the parameters an additional "$" sign is being assigned to awk -v option.
Could any one help me with this please.
#!/bin/ksh
head -1... (3 Replies)
Hi,
I am doing an AWK in ksh as below with the string to search to be read from variable but for some reason there is no output. It works when I hard code it.
awk 'substr($0,22,6)=="${VAR}"' XXX.txt' >YYY.txt
On reading other posts I tried below option,
'substr($0,22,6)=="/"${VAR}/""'
... (3 Replies)
Hi All,
I am using the below script which has awk command, but it is not returing the expected result. can some pls help me to correct the command.
The below script sample.ksh should give the result if the value of last 4 digits in the variable NM matches with the variable value DAT. The... (7 Replies)
Hi,
I need to set "prd" in the below command to a unix variable
nawk '/^#/ {next} FNR==NR {prd;next} !($0 in prd)'
So, this is what i did
fname=prd // unix shell variable
nawk -v fname=$fname '/^#/ {next} FNR==NR {fname;next} !($0 in fname)'But the value of fname i.e "prd" is not... (8 Replies)
Hi,
If i were to do this an print out the file, it will show as it is in the command
$ awk '/Privilege Use/ {P=0} /Object Access/ {P=1} P' AdvancedAudit.txt
Object Access
File System No Auditing
Registry No Auditing
Kernel... (1 Reply)
Discussion started by: alvinoo
1 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)