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Top Forums Programming Errors in Perl when using awk command Post 302586708 by rymnd_12345 on Tuesday 3rd of January 2012 05:01:16 AM
Old 01-03-2012
Hi curleb,

Thanks for the info, for now I've already created one using shell script this time. The script is now working and later I will put it in CRON.

Our server can only accept CRON entries provided you're a root user, so I've tried to input the script as a root user, my problem is that it's not functioning. Here is the analogy below:

Files that I want to remove are located in /home/user/USER_LOGS/, the script is also located in this directory. This is the script:
Code:
#!/usr/bin/sh

num_of_files=`ls /home/nsadm/USER_LOGS/ | grep UserActivity | grep UMB00 | wc -l`

if [ $num_of_files -gt 3 ]
then
remove=`ls -lrt /home/nsadm/USER_LOGS/ | grep UserActivity | grep UMB00 | head -1 | awk '{print $8}' | rm \`xargs\``
$remove
fi

but as per running the script when I'm in the directory /root (this is the default directory upon login as root user), it can't see the file and therefor it can't perform the rm function. This is what I've did as root user:
Code:
root:~ # /home/user/USER_LOGS/remover.sh
rm: cannot remove `09:46': No such file or directory

I think the problem here is that it can't locate the files that I want to delete under the /root directory. Can you help me how to enhance my script so that if ever I would like to put it in CRON it will function normally, by removing file on top and retaining only 3 files on it.


Please advice,
rymnd_12345

Last edited by vbe; 01-04-2012 at 12:30 PM.. Reason: code tag correction...
 

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bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
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