Let's say I write a simple script that contains the following:
date | awk '{print $1}'
date | awk '{print $2}'
Of course, when I run the script the output will look similar to:
Tue
Mar
What if I want my ouput to be on one line as follows:
Tue Mar
What changes would I need to... (2 Replies)
I have 2 files with sample data enclosed.
1. GL (already sorted in ascending order by Gl number)
Gl number*glname*Year*opening balance
1000*Interest Income*2006*100.00
1005*Rental Income*2006*0.00
...
2. Transactions (file is not sorted on GL number or any other field)
Branch*Year*Gl... (12 Replies)
Hi
I am fetcthing the data from the oracle database using SQLPLUS. Here is my script
#!/bin/ksh
echo `sqlplus -s <<EOF
set feedback off
set linesize 5000
set pages 0
set space 0
set echo off
set trimspool on
set colsep '|'
SELECT col1 , col2... (4 Replies)
Dear all
I require help with AWK regarding this situation
Input is :
fn1 12345
fn1 23456
fn3 231513
fn1 22325
fn3 123125
Desired output is
fn1 12345 23456 22325
fn3 231513 123125 (5 Replies)
when i try this awk its giving out put as below.
awk '!(/^$/||/--/||/selected/||/^ *$/){print $1}' tmp.txt
output
=====
1
2010-08-03-12.31.26.126000
how excluede the 1st line ? i mean i want output only 2nd line i.e 2010-08-03-12.31.26.126000; (5 Replies)
Hi;
i m running an command like;
getfacl $(find /home/fstl/testShell/ -type f -ls | awk '{print $11}')
and i m getting outpiut for all files in "testShell" folder as;
# file: home/fstl/testShell/.script1.sh.swp
# owner: root
# group: root
user:fstl:rw-
user:ajay:rw-
group:root:r--... (1 Reply)
Hi all,
I'm writing a simple awk code:
awk 'BEGIN {FS="|"};{print "Type\tNumber\ttypes\tTotal";};{print $1, "\t", $2, "\t", $3, "\t", $4, "\t";}' db_query.txt
it gives me the result:
Type Number types Total
XXX 498.0 5100.0 5274.661
Type Number types Total... (7 Replies)
Data
I was trying to write shell script which will be return the output in the below format
First i was trying to do these using sed.
sed -n '/.ksh/p' mainksh.ksh
sed -e 's/*\(.*\)/\1/g' mainksh.ksh
$RUN_DIR, $SUB_DIR and the variables which will be defined in the profile file.
when i am... (0 Replies)
Hi ,
I was trying to find files of a particular date and did that but then I also wanted to format a field based on some condition so had put another if else in awk.
Now it is getting the files of particular date or also the files which are matching that if else condition.
find . -name "*"... (1 Reply)
i would like to format the 9 character with suffix as "0".
i tried below it doesn't work.
>a=12345
> echo $a | awk '{printf "%-09s\n",$1}'
>12345
required output is 123450000
can you guys help me out ? (7 Replies)
Discussion started by: expert
7 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)