12-08-2011
Hi friend,
The code is not only for n=0, its in a for loop. Let me explain with an example.
If s contain a string "5270", then the loop continue for 4 times:
1st : 10*0 + 5 = 5
2nd : 10*5 + 2 = 52
3rd : 10*52 + 7 = 527
4th : 10*527 + 0 = 5270
which is the n value and a number instead of string.
Try to use some debugging tools and check the variables, u will understand it clearly...
This User Gave Thanks to siva shankar For This Post:
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ATOI(3) Linux Programmer's Manual ATOI(3)
NAME
atoi, atol, atoll, atoq - convert a string to an integer.
SYNOPSIS
#include <stdlib.h>
int atoi(const char *nptr);
long atol(const char *nptr);
long long atoll(const char *nptr);
long long atoq(const char *nptr);
DESCRIPTION
The atoi() function converts the initial portion of the string pointed to by nptr to int. The behaviour is the same as
strtol(nptr, (char **)NULL, 10);
except that atoi() does not detect errors.
The atol() and atoll() functions behave the same as atoi(), except that they convert the initial portion of the string to their return type
of long or long long. atoq() is an obsolete name for atoll().
RETURN VALUE
The converted value.
CONFORMING TO
SVID 3, POSIX.1, BSD 4.3, ISO/IEC 9899. ISO/IEC 9899:1990 (C89) and POSIX.1 (1996 edition) include the functions atoi() and atol() only;
C99 adds the function atoll().
NOTES
The non-standard atoq() function is not present in libc 4.6.27 or glibc 2, but is present in libc5 and libc 4.7 (though only as an inline
function in <stdlib.h> until libc 5.4.44). The atoll() function is present in glibc 2 since version 2.0.2, but not in libc4 or libc5.
SEE ALSO
atof(3), strtod(3), strtol(3), strtoul(3)
GNU
2000-12-17 ATOI(3)