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sh array and awk help...
Post 302579538 by gua76 on Tuesday 6th of December 2011 02:20:57 AM
12-06-2011
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10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I have a raw data file:
70,1,1,-53.25
70,1,1,,,,-57.50
70,1,1,,,,,,,,,,-48.00
I want to have a output file with the formatting below:
70,1,1,-53.25,,,,-57.50,,,,,-48.00
I mean if these rows have the first similar three variables which will be group into one row. And I try to write a... (1 Reply)
Discussion started by: anhtt
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2. Shell Programming and Scripting
Dear Experts,
I have a file containing text like below
123
456
789
012
345
I want to save each line in array.
and print each array index as per my requirement.
For Example array will print 456
array will print 012
Thanks for your Help. (14 Replies)
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3. Shell Programming and Scripting
Hi all,
i have a data array as follows.
array=ertfgj2345
array=456ttygkd
.
.
.
array=errdjt3235
so number or elements in the array can varies depending on how big the data input is.
now i have a variable, and it is $1 (there are $2, $3 and so on, i am only interested in $1).
... (9 Replies)
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4. Shell Programming and Scripting
Hi I am trying to get data from an array and input it into awk. Please see below:
###
#!/bin/bash
#declare array
declare -a ARRAY
exec 10</path/to/arrayfile
let count=0
while read LINE <&10; do
ARRAY=$LINE
((count++))
done
#close file
exec 10>&-
ENDLOOP=0 (10 Replies)
Discussion started by: rocket_dog
10 Replies
5. Shell Programming and Scripting
hi,
can somebody explain me this?
probably i am overlooking something but i dont know what
why is not printed "7 9 11" instead of this?
$ echo "" | awk '{for(i=1;i<=3;i++){j=7;a=j;j=j+2;} print a,a,a; }'
7 7 7thanks (2 Replies)
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6. Shell Programming and Scripting
Hello experts,
I'm stuck with this script for three days now. Here's what i need.
I need to split a large delimited (,) file into 2 files based on the value present in the last field.
Samp: Something.csv
bca,adc,asdf,123,12C
bca,adc,asdf,123,13C
def,adc,asdf,123,12A
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7. Shell Programming and Scripting
I'm trying to get the output from awk into a bash array. Here is my script.
#!/bin/bash
while :
do
app=$( osascript -e "tell application \"System Events\" to return name of every process whose frontmost is true" )
echo "$app"
if ava ]]
then
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8. Shell Programming and Scripting
Hello All,
Can you please help me with the below.
#!/bin/bash
ARR="No Differences In Stage Between HASH_TOTALS & HASH_TOTALS_COMP For UNINUM:0722075 PROVIDER:5 EXTRACT_DT:30-SEP-12 VER_NUM:1"
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9. Shell Programming and Scripting
Here's my code:
awk -F '' 'NR==FNR {
if (/time/ && $5>10)
A=$2" "$3":"$4":"($5-01)
else if (/time/ && $5<01)
A=$2" "$3":"$4-01":"(59-$5)
else if (/time/ && $5<=10)
A=$2" "$3":"$4":0"($5-01)
else if (/close/) {
B=0
n1=n2;
... (2 Replies)
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10. UNIX for Beginners Questions & Answers
Hello. I'm trying to figure out which one of these is not true about an awk array.
-You do not need to formally declare an array; it is created automatically on first assignment
-Array elements can only be addressed using an index
... (1 Reply)
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LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1) NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)