Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: How to Find number of days in a month in mmddyyyy format?
Top Forums Shell Programming and Scripting How to Find number of days in a month in mmddyyyy format? Post 302576676 by Gaurav198 on Friday 25th of November 2011 02:25:42 PM
Old 11-25-2011
Hi Felipe....did check with this long back...support diffrent format..
I had this one , but works for on year difrrence..i want to work in month diffrence format...

Code:
#! /usr/bin/ksh
#              ja fe ma ap ma ju ju ag se oc no de
set -A lasts 0 31 28 31 30 31 30 31 31 30 31 30 31
typeset -Z2 dmonth dday
year=2011
while ((year<2015)) ; do
        leap=0
        if ((!(year%100))); then
                ((!(year%400))) && leap=1
        else
                ((!(year%4))) && leap=1
        fi
        lasts[2]=28
        ((leap)) && lasts[2]=29
        month=1
        while ((month<13)); do
                day=1
                while((day<(lasts[month])+1)) ; do
                        dday=$day 
                        dmonth=$month
                        echo ${dmonth}${dday}${year}
                       ((day=day+1))
                done
                 ((month=month+1))
        done
        ((year=year+1))
done
exit 0

the above one works fine...but for years i have to narrow down to months
Last edited by fpmurphy; 11-26-2011 at 08:59 AM.. Reason: code tags please!
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Calc number of days in a month

Looking for some help on capturing the number of days in a month to set as a loop counter. Any ideas, please let me know. (3 Replies)
Discussion started by: flounder
3 Replies

2. Shell Programming and Scripting

Day of month and year to mmddyyyy

I have a date that looks like this: 2008/100:18:40:47.040 I need it to look like this: 2008 04 09 18 40 47 040 I have looked at datecalc and it doesn't seem like it takes the day of year for this year (or whatever year is input) and converts it into month and day. It also has to account... (2 Replies)
Discussion started by: ajgwin
2 Replies

3. Shell Programming and Scripting

calculate the number of days left in a month

does any one have any ideas how i would go about calculating the number of days left in the month from a bash script ?. I want to do some operations on a csv file according to the result (8 Replies)
Discussion started by: dunryc
8 Replies

4. Shell Programming and Scripting

Assigning number of days in the month to a variable

I am writing a script that requires the number of days in any given month. In the shell, I can use the command: cal `date +%m` `date +%Y`| grep -v '' | wc -w to give me the number of days in the month, but when I assign it to a variable: VAR=`cal `date +%m` `date +%Y`| grep -v '' | wc... (3 Replies)
Discussion started by: skaptakalian
3 Replies

5. Shell Programming and Scripting

Number of days in the previous month

Hi all. I am scripting in a POSIX shell on HPUX. I am running a script that needs to determine the number of days in a month. I found this on the forum and it works great: X=`cal $(date +%m) $(date +%Y) | grep -v '' | wc -w` The issue is that I am running the script on the 7th day of... (11 Replies)
Discussion started by: lyoncc
11 Replies

6. Shell Programming and Scripting

Number of days in month from certain parameters

Hi, I have an issue in date processing, the issue is I have a month as an int ( 1 - 12 ), the weekday as int ( 0 - 6 , 0 = Sunday), and the week day in month as int ( 0 - 5, 5 = last ex: first sunday, last monday, third tuesday ... ), now from those three parameters is there a possible way to... (5 Replies)
Discussion started by: modn3
5 Replies

7. Programming

Number of days in month from certain parameters, c programming request.

Hi, I have an issue in date processing, the issue is I have a month as an int ( 1 - 12 ), the weekday as int ( 0 - 6 , 0 = Sunday), and the week day in month as int ( 0 - 5, 5 = last ex: first sunday, last monday, third tuesday ... ), now from those three parameters is there a possible way to... (2 Replies)
Discussion started by: modn3
2 Replies

8. Shell Programming and Scripting

display number of days in current month

hi all searched google and here, cant find and am begining to suspect there is no options for this. shell = born with either the date or cal command I need to display the number of days in current month. can anyone point me in the right direction? (10 Replies)
Discussion started by: rontopia
10 Replies

9. Shell Programming and Scripting

find file older than one month not by x days olds

Hi, I would like to ask about some question on the -mtime option in the find command. I want to move a log files older than one month and planning to used the find -mtime +30 but i have some clarrification does -mtime +30 or -30 refer to x days beyond or between so how about the month. suppose... (2 Replies)
Discussion started by: jao_madn
2 Replies

10. Shell Programming and Scripting

Number of days in current month

I have a homework assignment: ---------------------------------------- "Display" the number of days in the current month. For example: September 1996 has 30 days ---------------------------------------- I am trying to just display the head of cal to start the sentence. eg. cal | head ... (1 Reply)
Discussion started by: eaafuddy
1 Replies

LEARN ABOUT DEBIAN

cyrus-arbitron

ARBITRON(8)						      System Manager's Manual						       ARBITRON(8)

 *

NAME

       arbitron - arbitron mailboxes

SYNOPSIS

       arbitron [ -C config-file ] [ -o ] [ -u ] [ -l ] [ -p months ]
		[ -d days | -D mmddyyyy[:mmddyyyy] ] mailbox...

DESCRIPTION

       Arbitron  collects  and	reports readership statistics for mailboxes on the server.  It also optionally prunes the mailboxes of Seen state
       for dormant users.

       Arbitron produces one line of output per mailbox, reporting the mailbox name followed by a space, followed by the number of readers (and if
       -u  is specified, followed by a colon and a comma-separated list of the readers userids), and if -o is not specified, another space and the
       number of subscribers (and if -u is specified, followed by a colon and a comma-separated list of the subscribers userids).  IMPORTANT: This
       format is subject to change in future versions.

       Each  "reader"  is  a distinct authentication identity which has "s" rights to the mailbox and which has SELECTed the mailbox within either
       the past days days or the specified date range.	Users are not counted as reading their own personal mailboxes.	Personal mailboxes are not
       reported unless there is at least one reader other than the mailboxes owner.

       Arbitron reads its configuration options out of the imapd.conf(5) file unless specified otherwise by -C.

OPTIONS

       -C config-file
	      Read configuration options from config-file.

       -o     "old way" -- do not report subscribers.

       -u     Report userids in addition to the count(s).

       -l     Enable long reporting (comma delimited table consisting of mbox, userid, r/s, start time, end time).

       -d days
	      Count as a reader an authentication identity which has SELECTed the mailbox within days days.  Default is 30.

       -D mmddyyyy[:mmddyyyy]
	      Count  as  a  reader  an	authentication	identity  which  has SELECTed the mailbox within the given date range.	The start date and
	      optional end date are specified as 2-digit month of the year, 2-digit day of the month, and 4-digit year.  If the end  date  is  not
	      specified, then the current system time is used as the end time.

       -p months
	      Prune Seen state for users who have not SELECTed the mailbox within months months.  Default is infinity.

FILES

       /etc/imapd.conf

CMU
								   Project Cyrus						       ARBITRON(8)
All times are GMT -4. The time now is 04:11 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy