Sponsored Content
Top Forums Shell Programming and Scripting Don't understand AWK asort behaviour Post 302576067 by binlib on Wednesday 23rd of November 2011 01:57:37 PM
Old 11-23-2011
Code:
for (i=1; i<=length(T); i++) printf(T[i]);

caused the array T to be filled with many null values. At the beginning, length(T) was 6. When i was incremented to 4, it created new array element T[4], etc.
This User Gave Thanks to binlib For This Post:
 

8 More Discussions You Might Find Interesting

1. UNIX for Advanced & Expert Users

don't understand the unix script

if {"$my_ext_type" = MAIN]; then cd $v_sc_dir Filex.SH $v_so_dir\/$v_fr_file Can somebody tell me what does this suggest. I am pretty new to unix and I am getting confused. What i understood from here is If we have a file extension name as MAIN which we have then we change the directory to... (1 Reply)
Discussion started by: pochaman
1 Replies

2. Solaris

I don`t understand how It work (about startup script)?

Hi all. The startup script in /usr/local/bin. After user login the script run an application. Iwould in the same way run the another application. How to make It similar? Where I must to look? Regards. (3 Replies)
Discussion started by: wolfgang
3 Replies

3. Shell Programming and Scripting

Don't understand how RS functions in awk

I learn using RS in awk to extract portion of file in this forum which is wonderful solution to the problem. However, I don't understand how exactly it operates. I don't quite understand the mechanism behind how searching for /DATA2/ can result in extracting the whole section under "DATA2" ... (3 Replies)
Discussion started by: joe228
3 Replies

4. Homework & Coursework Questions

I don't understand some basics..

Use and complete the template provided. The entire template must be completed. If you don't, your post may be deleted! 1. The problem statement, all variables and given/known data: 1)find all lines in file ,myf that contain all the words cat dog and mouse in any order and start with the letter... (1 Reply)
Discussion started by: cudders
1 Replies

5. UNIX for Dummies Questions & Answers

Another Simple BASH command I don't understand. Help?

I have a text file called file1 which contains the text: "ls -l" When I enter this command: bash < file1 > file1 file1 gets erased. However if I enter this command: bash < file1 > newfile the output from "ls -l" is stored in newfile. My question is why doesn't file1's text ("ls -l") get... (3 Replies)
Discussion started by: phunkypants
3 Replies

6. Shell Programming and Scripting

Perl syntax that I don't understand.

I'm just trying to confirm that I understand someone's code correctly. If someone has code that says: $foo ||= mysub(); I'm assuming that it means if $foo is nothing or undef, then assign it some value via mysub(). If I'm wrong on this, please let me know. Also, what's the difference... (4 Replies)
Discussion started by: mrwatkin
4 Replies

7. UNIX for Dummies Questions & Answers

trying to compile and don't understand error message

this is my program i am trying to compile /* filedata -- display information about a file */ #include <stdlib.h> #include <stdio.h> #include <sys/stat.h> #include <sys/types.h> /* * use octarray for determing * if permission bits set */ static short octarray = {0400, 0200, 0100,... (2 Replies)
Discussion started by: heywoodfloyd
2 Replies

8. UNIX for Dummies Questions & Answers

I don't understand conditions :(

Hi there, I have a very general question. I'm rather new to (bash) shell scripting and I don't understand how conditions work... I've read numerous tutorials but I don't get it. I really don't. Sometime what I do works, sometime it doesn't and that's frustating. So what's the actual difference... (0 Replies)
Discussion started by: hypsis
0 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 10:49 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy