11-22-2011
Cut fields from /etc/passwd file into variables?
The script must ask the user to enter the user name and check whether the user exists in /etc/passwd (you must allow the partial usernames also). If the username exists, display the details as:
List of users
Login Name:
User ID:
--------------------------------------------------------------
I have started by reading the username:
read username;
Once it pulls my username from the variable I want to cut the first and second field from the /etc/passwd file into their own variables. But this is not working for me and I cannot seem to figure out how I should do this. This is the closest I have came:
grep -E "$username" /etc/passwd|login=$(cut -f1)|userid=$(cut -f2);
Any help would be greatly appreciated!
Regards,
Justin
10 More Discussions You Might Find Interesting
1. Solaris
Describe what the output of the command “cut -d: -f4 /etc/passwd | more” would be? (3 Replies)
Discussion started by: wickbc
3 Replies
2. UNIX for Dummies Questions & Answers
Hi,
I am looking for a method to get column13 to column 50 data from the 1st line of a multiline reord. The records are stored in a large file and are separated by newline. sample format is
(data in red is to be extracted)
<header>
A001dfhskhfkdsh hajfhksdhfjh... (3 Replies)
Discussion started by: sunayana3112
3 Replies
3. Shell Programming and Scripting
I'm working on formatting some attendance data to meet a vendors requirements to upload to their system. With some help on the forums here, I have the data close. But they've since changed what they want.
The vendor wants me to submit three fields to them. Field 1 is the studentid field,... (4 Replies)
Discussion started by: axo959
4 Replies
4. Shell Programming and Scripting
Hi,
I have data in following format.
10001, John, Daves, Architecture, -2219
10002, Jim, Cirners, Businessman, -2219
1003, Tom, Katch, Engineer, -14003
I want to select the last column of the above given file and paste it on a different file in the following manner.
File TEST column... (11 Replies)
Discussion started by: kam786sim
11 Replies
5. Shell Programming and Scripting
Hi,
I am writing a code where the file is a pipe delimited and I would need to extract the 2nd part of field2 if it is "ATTN", "C/O" or "%" and check to see if field9 is populated or not. If field9 is already populated then leave it as is but if field9 is not populated then take the 2nd part of... (3 Replies)
Discussion started by: msalam65
3 Replies
6. UNIX for Dummies Questions & Answers
Okay, I've made threads on extracting fields and comparing strings in separate files in .csv's. I've written the following code with intentions of learning more.
I just want this one question answered: How can I assign fields from a file(comma separated) to variables?
My goal is to check... (0 Replies)
Discussion started by: chickeneaterguy
0 Replies
7. UNIX for Dummies Questions & Answers
Hi!
i want to extract from /etc/passwd file,the user and user info fileds, to a another file.I've tried this:
cut -d ':' -f1 ':' -f6 < file
but cut can be used to extract olny one field and not two.
maybe with awk is this possible? (4 Replies)
Discussion started by: strawhatluffy
4 Replies
8. UNIX for Dummies Questions & Answers
I'm looking for some documentation on what the different fields mean in the output of passwd -S username:
passwd -S foo
foo PS 2012-03-20 0 70 3 -1 (Password set, MD5 crypt.)
I think the date given is the date of the last password change, the 0 after that is the minimum password age, and... (2 Replies)
Discussion started by: Anne Neville
2 Replies
9. UNIX for Beginners Questions & Answers
I'm a complete beginner in UNIX (and not a computer science student either), just undergoing a tutoring course. Trying to replicate the instructions on my own I directed output of the ls listing command (lists all files of my home directory ) to My_dir.tsv file (see the screenshot) to make use of... (9 Replies)
Discussion started by: scrutinizerix
9 Replies
10. UNIX for Beginners Questions & Answers
I'm trying to use awk to count the occurrences of two matching fields of a CSV file.
For instance, for data that looks like this...
Joe,Blue,Yes,No,High
Mike,Blue,Yes,Yes,Low
Joe,Red,No,No,Low
Joe,Red,Yes,Yes,Low
I've been trying to use code like this...
countvar=`awk ' $2~/$color/... (4 Replies)
Discussion started by: nmoore2843
4 Replies
LEARN ABOUT REDHAT
hesiod_free_passwd
HESIOD(3) Library Functions Manual HESIOD(3)
NAME
hesiod_getpwnam, hesiod_getpwuid, hesiod_free_passwd - Hesiod functions for retrieving passwd information
SYNOPSIS
#include <hesiod.h>
struct passwd *hesiod_getpwnam(void *context, const char *name)
struct passwd *hesiod_getpwuid(void *context, uid_t uid)
void hesiod_free_passwd(void *context, struct passwd *pw)
cc file.c -lhesiod
DESCRIPTION
This family of functions allows you to retrieve passwd database information using Hesiod. To perform lookups, you need an initialized Hes-
iod context; see hesiod(3) for details. You may look up passwd information by name or by uid; information is returned in the same format
as by getpwnam or getpwuid. It is the caller's responsibility to call hesiod_free_passwd with the returned passwd entry to free the
resources used by the passwd entry.
Hesiod queries for passwd information are made using the ``passwd'' or ``uid'' Hesiod type, using either the username or the decimal repre-
sentation of the uid as the Hesiod name. The corresponding records should be a colon-separated list of fields giving the username,
encrypted password, uid, gid, GECOS information, home directory, and shell of the user.
RETURN VALUES
On failure, hesiod_getpwnam and hesiod_getpwuid return NULL and set the global variable errno to indicate the error.
ERRORS
These calls may fail for any of the reasons the routine hesiod_resolve may fail.
SEE ALSO
hesiod(3)
30 November 1996 HESIOD(3)