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Full Discussion: Array and Vector
Top Forums Programming Array and Vector Post 302573733 by Corona688 on Tuesday 15th of November 2011 10:39:37 AM
Old 11-15-2011
Quote:
Originally Posted by shamrock
I am not sure as to what part of an array of pointers to struct type dont you get...
I get it. I just don't understand what makes you think it's anything like a vector.
Quote:
its vectorized as each can be located anywhere in memory
C++ vectors are stored contiguously in memory, and allocated together, not individually. You may be thinking of sparse memory, like a C++ map<>?

Except this is a poor way to do sparse memory, too. You'd do that with a list of some sort, so you don't even store NULL pointers for empty elements.

What you've got could be used to build a hash table, perhaps.
 

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Tie::SubstrHash(3pm)					 Perl Programmers Reference Guide				      Tie::SubstrHash(3pm)

NAME
Tie::SubstrHash - Fixed-table-size, fixed-key-length hashing SYNOPSIS
require Tie::SubstrHash; tie %myhash, 'Tie::SubstrHash', $key_len, $value_len, $table_size; DESCRIPTION
The Tie::SubstrHash package provides a hash-table-like interface to an array of determinate size, with constant key size and record size. Upon tying a new hash to this package, the developer must specify the size of the keys that will be used, the size of the value fields that the keys will index, and the size of the overall table (in terms of key-value pairs, not size in hard memory). These values will not change for the duration of the tied hash. The newly-allocated hash table may now have data stored and retrieved. Efforts to store more than $table_size elements will result in a fatal error, as will efforts to store a value not exactly $value_len characters in length, or reference through a key not exactly $key_len characters in length. While these constraints may seem excessive, the result is a hash table using much less internal memory than an equivalent freely-allocated hash table. CAVEATS
Because the current implementation uses the table and key sizes for the hashing algorithm, there is no means by which to dynamically change the value of any of the initialization parameters. The hash does not support exists(). perl v5.12.1 2010-04-26 Tie::SubstrHash(3pm)
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