Can anyone explain to me why the first line doesn't work and the second seems to work fine. I am trying to find all occurances of text within a certain column (col 13) that start with the character V, I suppose it sounds simple but I have tried using the following but don't really understand what... (2 Replies)
Hi all,
I can run the following script using nawk..However, I find that teh server dun support nawk.. May I know how to change teh script to use awk such that it will work? Very urgent.. thx!
nawk 'BEGIN {FS=OFS=","}
NR==FNR{arr=$2;next}
$0 !~ "Documentation"{print $0;next} ... (2 Replies)
i'm new to shell scripting and have a problem please help me
in the script i have a nawk block which has a variable count
nawk{
.
.
.
count=count+1
print count
}
now i want to access the value of the count variable outside the awk block,like..
s=`expr count / m`
(m is... (5 Replies)
Hi Guys,
i tried these two commands. First in awk and nawk.
The nawk command is running fine but the awk command is throwing error.
What is wrong with the awk command. There are lot of awk commands running fine in my system
d003:/usr/local/dsadm/dsprod>nawk 'NR = 1 {print " "$0}' a.txt
... (6 Replies)
Why do they do two different things? Like on one version of UNIX you can use awk, but tehn if you move to Solaris then awk becomes something crap and you need to use nawk instead! whY!?!?!?! (4 Replies)
Hi everyone,
i am new to unix , so i want to know what is the use of awk and nawk.
because in most of the place this cmds were used.
so, if anyone provied the basic idea of this cmds, it will be much helpfull for me . . ..
Thnks in Advance :) (9 Replies)
I am trying to use either awk or nawk in ksh88 to grep the word "Reason" in multiple files and than print the lines that say "Reason" in a particular format that is different from how they would normally print. The original input is as follows:
... (10 Replies)
Hi Guys,
This is the Input:
<xn:MeContext id="XXX012">
<xn:ManagedElement id="1">
<xn:attributes>
<xn:userLabel>XXX012</xn:userLabel>
<xn:swVersion>R58E68</xn:swVersion>
</xn:attributes>
</xn:ManagedElement>
</xn:MeContext>... (4 Replies)
Discussion started by: smarones
4 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)