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Top Forums Shell Programming and Scripting Date format check and replace string in PERL Post 302570961 by irudayaraj on Saturday 5th of November 2011 03:05:36 AM
Old 11-05-2011
This if fine but will make the script look big. I need to do this in a single line because there are 3 more patterns for month..."month", "mon" too.

Quote:
$dateformat =~ s/yyyy/$Y1/g;
$dateformat =~ s/yy/$Y2/g;
$dateformat =~ s/mm/$m1/;
$dateformat =~ s/dd/$d1/;
The above four should be done in a single line.
 

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DATEFMT_GET_PATTERN(3)							 1						    DATEFMT_GET_PATTERN(3)

IntlDateFormatter::getPattern - Get the pattern used for the IntlDateFormatter

	Object oriented style

SYNOPSIS
public string IntlDateFormatter::getPattern (void ) DESCRIPTION
Procedural style string datefmt_get_pattern (IntlDateFormatter $fmt) Get pattern used by the formatter. PARAMETERS
o $fmt - The formatter resource. RETURN VALUES
The pattern string being used to format/parse. EXAMPLES
Example #1 datefmt_get_pattern(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'MM/dd/yyyy' ); echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt); echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0); datefmt_set_pattern($fmt,'yyyymmdd hh:mm:ss z'); echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt); echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0); ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'MM/dd/yyyy' ); echo 'pattern of the formatter is : ' . $fmt->getPattern(); echo 'First Formatted output is ' . $fmt->format(0); $fmt->setPattern('yyyymmdd hh:mm:ss z'); echo 'Now pattern of the formatter is : ' . $fmt->getPattern(); echo 'Second Formatted output is ' . $fmt->format(0); ?> The above example will output: pattern of the formatter is : MM/dd/yyyy First Formatted output is 12/31/1969 Now pattern of the formatter is : yyyymmdd hh:mm:ss z Second Formatted output is 19690031 04:00:00 PST SEE ALSO
datefmt_set_pattern(3), datefmt_create(3). PHP Documentation Group DATEFMT_GET_PATTERN(3)
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