Sponsored Content
Top Forums Shell Programming and Scripting Date format check and replace string in PERL Post 302570957 by ahamed101 on Saturday 5th of November 2011 02:41:25 AM
Old 11-05-2011
Something like this?
Code:
#!/bin/bash

dateformat='yymmdd';
Y1=2011;
Y2=11;
m1=11; #---- current month november
d1=05; #---- current day
dateval=$(echo $dateformat | sed "s/yyyy/$Y1/;s/yy/$Y2/;s/mm/$m1/;s/dd/$d1/")
echo $dateval

--ahamed
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Check the format of Date

Hi, I have a date field in my input file. I just want to check if its in the format "DD-MM-YYYY". Is there any command which can achieve this? Thanks and Regards, Abhishek (2 Replies)
Discussion started by: AAA
2 Replies

2. Shell Programming and Scripting

How to search a date format from a file an replace with a string in PERL

I am very new to Perl. I am struggling so hard to search a date (such as 10/09/2009, 10-09-2009) from a text file and replace with a string (say DATE) using Perl. Please help me out. Thanks in advance. Regds Doren (4 Replies)
Discussion started by: my_Perl
4 Replies

3. Shell Programming and Scripting

Check input date format?

how to check input date format. for example $input_date must be in format dd.mm.gg script is execute like this: bin/script1.sh 14.12.2009 script1.sh code: #!/bin/sh input_date=$1 CMD="/app/si/test/test.sh $input_date" echo "*****" $CMD (2 Replies)
Discussion started by: waso
2 Replies

4. Shell Programming and Scripting

PERL String to Date (Custom format yyyymmdd to dd-mon-yyyy)

Hi All, I am learning PERL for one of the projects, and in one of these scripts, I read a flat text file and print in the terminal. The problem is, the text file has a date field. The format is yyyymmdd. I need to display this as dd-mon-yyyy. Any ideas to do this? Thanks a lot for the... (9 Replies)
Discussion started by: guruparan18
9 Replies

5. Shell Programming and Scripting

Need to check date format yyyymm

My source file having one date column. The formate of the date column is yyyymm. I need to validate whether all the rows are in same format in the given file. If it is not I have captured that records in a separate file. I am very new to Unix. I don't how to achieve this. Plz help me to achieve... (2 Replies)
Discussion started by: suresh01_apk
2 Replies

6. Shell Programming and Scripting

PERL : hhmiss - Date format check and replace

I have a filename, This can be any of any format, I want to check if the filename has hours,mins and seconds part. If it is present, i want to replace it with a " * " (star symbol) output needed: IMP: The time part can be in any pattern. How can this be done?:confused:... (3 Replies)
Discussion started by: irudayaraj
3 Replies

7. Shell Programming and Scripting

finding date numeral from file and check the validity of date format

hi there I have file names in different format as below triss_20111117_fxcb.csv triss_fxcb_20111117.csv xpnl_hypo_reu_miplvdone_11172011.csv xpnl_hypo_reu_miplvdone_11-17-2011.csv xpnl_hypo_reu_miplvdone_20111117.csv xpnl_hypo_reu_miplvdone_20111117xfb.csv... (10 Replies)
Discussion started by: manas_ranjan
10 Replies

8. Shell Programming and Scripting

Perl code to check date and check files in particular dir

Hi Experts, I am checking how to get day in Perl. If it is “Monday” I need to process…below is the pseudo code. Can you please prove the code for below condition. if (today=="Monday" ) { while (current_time LESS THAN 9:01 AM) ... (1 Reply)
Discussion started by: ajaypatil_am
1 Replies

9. Shell Programming and Scripting

How to check if date format is correct?

Hi! how do i know if the input is the same as the required date format? the date should be dd/mm/YYYY ex. 2/3/2012 or 15/11/2012 all the following conditions must return an error: *input of string *day is > 31 or < 1 *month is > 12 or < 1 *year is < 2013 suppose the date format is stored... (1 Reply)
Discussion started by: angilulu
1 Replies

10. Shell Programming and Scripting

Check Date Format And Email Out

Hello All, I have a requirement where i need to get the EXTRACT_DATE from a file and check if the date is of valid format or not and then mail it if it is not valid. Appreciate if you can help me with this. I did the following so far. awk '{for(i=1;i++<=NF;)if($i~/^EXTRACT_DATE/) print $i}'... (11 Replies)
Discussion started by: Ariean
11 Replies
DATEFMT_IS_LENIENT(3)							 1						     DATEFMT_IS_LENIENT(3)

IntlDateFormatter::isLenient - Get the lenient used for the IntlDateFormatter

	Object oriented style

SYNOPSIS
public bool IntlDateFormatter::isLenient (void ) DESCRIPTION
Procedural style bool datefmt_is_lenient (IntlDateFormatter $fmt) Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly. PARAMETERS
o $fmt - The formatter resource. RETURN VALUES
TRUE if parser is lenient, FALSE if parser is strict. By default the parser is lenient. EXAMPLES
Example #1 datefmt_is_lenient(3) example <?php $fmt = datefmt_create( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, 'dd/mm/yyyy' ); echo 'lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } datefmt_set_lenient($fmt,false); echo 'Now lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } datefmt_parse($fmt, '35/13/1971'); echo " Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> Example #2 OO example <?php $fmt = new IntlDateFormatter( 'en_US', IntlDateFormatter::FULL, IntlDateFormatter::FULL, 'America/Los_Angeles', IntlDateFormatter::GREGORIAN, "dd/mm/yyyy" ); echo "lenient of the formatter is : "; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0){ echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } $fmt->setLenient(FALSE); echo 'Now lenient of the formatter is : '; if ($fmt->isLenient()) { echo 'TRUE'; } else { echo 'FALSE'; } $fmt->parse('35/13/1971'); echo " Trying to do parse('35/13/1971'). Result is : " . $fmt->parse('35/13/1971'); if (intl_get_error_code() != 0) { echo " Error_msg is : " . intl_get_error_message(); echo " Error_code is : " . intl_get_error_code(); } ?> The above example will output: lenient of the formatter is : TRUE Trying to do parse('35/13/1971'). Result is : -2147483 Now lenient of the formatter is : FALSE Trying to do parse('35/13/1971'). Result is : Error_msg is : Date parsing failed: U_PARSE_ERROR Error_code is : 9 SEE ALSO
datefmt_set_lenient(3), datefmt_create(3). PHP Documentation Group DATEFMT_IS_LENIENT(3)
All times are GMT -4. The time now is 05:29 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy