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Full Discussion: Awk numeric range match only one digit?
Top Forums Shell Programming and Scripting Awk numeric range match only one digit? Post 302569804 by meridionaljet on Tuesday 1st of November 2011 03:25:03 PM
Old 11-01-2011
Awk numeric range match only one digit?
Hello,

I have a text file with lines that look like this:

Code:
1974 12 27 -0.72743 -1.0169 2 1.25029 
1974 12 28 -0.4958 -0.72926 2 0.881839 
1974 12 29 -0.26331 -0.53426 2 0.595623 
1974 12 30 7.71432E-02 -0.71887 3 0.723001 
1974 12 31 0.187789 -1.07114 3 1.08748 
1975 1 1 0.349933 -1.02217 3 1.08041 
1975 1 2 0.401935 -1.21842 3 1.28301 
1975 1 3 0.545325 -1.0697 3 1.20068 
1975 1 4 0.240114 -1.05894 3 1.08583

I want awk to search the 2nd field (which represents months) and spit out lines where that field's numeric value falls within a certain range. My code for this is:

Code:
echo "Please pick a numerical range (e.g. 6-9 for Jun-Sep)"
read months
awk '$2 ~ /['$months']/ {print $0}' file1.txt > file2.txt

This works great for, say, the range 6-9, but the problem is that for a month system, the numbers 1 and 2 will be matched in the numbers 10, 11, and 12, so a search for "1-3" (January-March) will return October, November, and December values that I don't want. I have tried forcing only a 1-digit match using:

Code:
awk '$2 ~ /['$months']{1}/ {print $0}' mjo-tmp0.txt > mjo-tmp1.txt

...but that doesn't work(it returns nothing), and even if it did, it would eliminate searches for double-digit months like "10-12". Is there a way for me to get awk to search only for exact matches within the numerical range? Any help would be appreciated.
 

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LEARN ABOUT OSX

digittoint_l

DIGITTOINT(3)						   BSD Library Functions Manual 					     DIGITTOINT(3)

NAME

     digittoint, digittoint_l -- convert a numeric character to its integer value

LIBRARY

     Standard C Library (libc, -lc)

SYNOPSIS

     #include <ctype.h>

     int
     digittoint(int c);

     #include <xlocale.h>
     #include <ctype.h>

     int
     digittoint_l(int c, locale_t loc);

DESCRIPTION

     The digittoint() function converts a numeric character to its corresponding integer value.  The character can be any decimal digit or hexa-
     decimal digit.  With hexadecimal characters, the case of the values does not matter.

     While the digittoint() function uses the current locale, the digittoint_l() function may be passed a locale directly. See xlocale(3) for more
     information.

RETURN VALUES

     The digittoint() function always returns an integer from the range of 0 to 15.  If the given character was not a digit as defined by
     isxdigit(3), the function will return 0.

SEE ALSO

     ctype(3), isdigit(3), isxdigit(3), xlocale(3)

BSD
								   April 6, 2001							       BSD
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