#!/bin/bash
TODAY=`/bin/date +%d`
TOMORROW=`/bin/date +%d -d "1 day"`
# See if tomorrow's day is less than today's
if [ $TOMORROW -lt $TODAY ]; then
exit 0
fi
exit 1
it will run for every day which less than tomorrow, like it will on 29 coz 29 is less than 30, it will run on 30 coz 30 is less than 31st....what happen if date is 28th Feb...!!!
and my requirement is it should run on last day of every month....I can't do scheduling in crontab, due to some constrain......please help me in achieving it through script.....
Thanks in advance
Moderator's Comments:
Use code tag! See PM.
Last edited by zaxxon; 10-31-2011 at 06:11 AM..
Reason: code tags, see PM
Hi ,
I am relatively new to unix...
Can u pls help me out to find out if the first day of the month is a working day ie from (Monday to Friday)...using Date and If clause in Korn shell..
This is very urgent.
Thanks for ur help... (7 Replies)
I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?
How do I exclude Monday if the 2nd day of the month falls on a Monday?
Thanks.
I tried this:
0 0 2 * 0,2-6 command
And I know this doesnt... (2 Replies)
Hi All,
I need to find the previous month last day minus one day, using shell script. Can you guys help me to do this.
My Requirment is as below:
Input for me will be 2000909(YYYYMM)
I need the previous months last day minus 1 day timestamp. That is i need 2000908 months last day minus ... (3 Replies)
I am using the code below modified from a post I saw here regarding having the script write out future dates. The problem is that instead of making 8/1 it makes 7/32! Please help!
yy=`date +%Y`
mm=`date +%m`
dd=`date +%d`
echo "Today is : $yy $mm $dd"
#!/usr/bin/ksh
date '+%m... (5 Replies)
Hello All,
I am trying to come up with a shell script to count a specific word in a logfile on each day of this month, last month and the month before. I need to produce this report and email it to customer.
Any ideas would be appreciated! (5 Replies)
Hello Experts,
I have a script which i want to run the on last day of every month.
let say I have backup.sh script which i want to run it every month last day.
Can anyone please help :confused:
thanks (4 Replies)
Hello Guys,
I have a questions regarding running a shell script every second working day each month.
I have no clue how solve this problem :wall:.
Important is that it has to be the second working (Mo-Fr).
Example: If 1st and 2nd Days of month are Sat and Sun the script must run on 4th day... (5 Replies)
hello,
I have many files called day001, day002, day003 and I want to rename them by day20070101, day20070102, etc.
I need to do it for several years and leap years as well.
What is the best way to do it ?
Thank you. (1 Reply)
I am looking for a unix script which could run a job on 2, 4 and 7 working day of the month.
if the days are falling on the saturday/sunday. it should run on the next day.
Thank you.. (9 Replies)
Discussion started by: tradingspecial
9 Replies
LEARN ABOUT CENTOS
cal
CAL(1) User Commands CAL(1)NAME
cal - display a calendar
SYNOPSIS
cal [options] [[[day] month] year]
DESCRIPTION
cal displays a simple calendar. If no arguments are specified, the current month is displayed.
OPTIONS -1, --one
Display single month output. (This is the default.)
-3, --three
Display prev/current/next month output.
-s, --sunday
Display Sunday as the first day of the week.
-m, --monday
Display Monday as the first day of the week.
-j, --julian
Display Julian dates (days one-based, numbered from January 1).
-y, --year
Display a calendar for the current year.
-V, --version
Display version information and exit.
-h, --help
Display help screen and exit.
PARAMETERS
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: cal 89 will not display a calendar
for 1989.
Two parameters denote the month (1 - 12) and year.
Three parameters denote the day (1-31), month and year, and the day will be highlighted if the calendar is displayed on a terminal. If no
parameters are specified, the current month's calendar is displayed.
A year starts on Jan 1. The first day of the week is determined by the locale.
The Gregorian Reformation is assumed to have occurred in 1752 on the 3rd of September. By this time, most countries had recognized the ref-
ormation (although a few did not recognize it until the early 1900's). Ten days following that date were eliminated by the reformation, so
the calendar for that month is a bit unusual.
HISTORY
A cal command appeared in Version 6 AT&T UNIX.
AVAILABILITY
The cal command is part of the util-linux package and is available from ftp://ftp.kernel.org/pub/linux/utils/util-linux/.
util-linux June 2011 CAL(1)
10-31-2011
