Hi,
I'm need to do some addition and multiplication of scientific nottaion numbers, in the form 34.23423e-10 for example.
I was echoing the list of numbers to stdout, then using bc -l, then I find that this does not seem to work for numbers with exponential notation. Could someone help me out... (1 Reply)
Hello,
I've tried searching the forum for an answer to my question, but without any luck...
I have a datafile looking simplified as follows:
01 02 03 04 05 06
07 08 09 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
I want to reverse it by rearranging all the numbers from last to... (16 Replies)
Hi all,
I have created a script which adding two columns and removing two columns for all files.
Filename: Cust_information_1200_201010.txt
Source Data:
"1","Cust information","123","106001","street","1-203 high street"
"1","Cust information","124","105001","street","1-203 high street"
... (0 Replies)
Hi All,
I have tried few things with this but it did not help much.
I have some 200,000 files in a directory. There are two sets of files.
1. Files with extension .dat with file names like these (1.dat, 2.dat, 5.dat, 8.dat....200000.dat)
2. Another set of files with .txt extension and... (5 Replies)
Dear all,
I have one file (see below) with more then 100 columns, and need only column which has GType in label with Alphabets, please help me to remove this columns with numbers.
input file is
n.201.GType n-201.Theta n-201.R n_1.GType n_1.Theta n_1.R n_7.GType ... (1 Reply)
the following is used to add numbers:
echo 7 47 47 44 4 3 3 3 3 3 | awk '{ for(i=1; i<=NF;i++) j+=$i; print j; j=0 }'
how do i multiply OR subtract a row of numbers using the above tactic? (8 Replies)
Hi again. Sorry for all the questions — I've tried to do all this myself but I'm just not good enough yet, and the help I've received so far from bartus11 has been absolutely invaluable. Hopefully this will be the last bit of file manipulation I need to do.
I have a file which is formatted as... (4 Replies)
Hi Folks,
I have a file with 2 columns TAB delimited and I want to add '1' to the first column and subtract '-1' from the second column.
What I have tried so far is;
awk -F"\t" '{ $1-=1;$2+=1}1' OFS='\t' file
File
0623 0623
0624 0624
0643 0643
1059 1037
1037 1037
1038 1038... (2 Replies)
This helped get me started.
https://www.unix.com/unix-for-dummies-questions-and-answers/157026-need-command-search-numbers-greater-than-3000-a.html
This is the command I am using. I am trying to find numbers greater than 70 in column 5. I do not know if it is getting confused because there... (6 Replies)
Discussion started by: cokedude
6 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)