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Top Forums Shell Programming and Scripting Checking whether the file exists under a directory and doing a diff Post 302566643 by otheus on Thursday 20th of October 2011 06:23:34 PM
Old 10-20-2011
In each dir do an "ls -1" to give you a single column of files. Output each to a new file. Then use comm to find the common and distinct files in each.

Code:
dev$ ls -1 >/tmp/dev.ls
dev$ cd ../uat
uat$ ls -1 >/tmp/uat.ls ;
cd /tmp
tmp$ comm dev.ls uat.ls

The man page on comm will tell you how to interpret the output and how to run it to get the results you want.

Last edited by otheus; 10-20-2011 at 11:50 PM..
 

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COMM(1) 						    BSD General Commands Manual 						   COMM(1)

NAME
comm -- select or reject lines common to two files SYNOPSIS
comm [-123f] file1 file2 DESCRIPTION
The comm utility reads file1 and file2, which should be sorted lexically, and produces three text columns as output: lines only in file1; lines only in file2; and lines in both files. The filename ``-'' means the standard input. The following options are available: -1 Suppress printing of column 1. -2 Suppress printing of column 2. -3 Suppress printing of column 3. -f Fold case in line comparisons. Each column will have a number of tab characters prepended to it equal to the number of lower numbered columns that are being printed. For example, if column number two is being suppressed, lines printed in column number one will not have any tabs preceding them, and lines printed in column number three will have one. comm assumes that the files are lexically sorted; all characters participate in line comparisons. EXIT STATUS
comm exits 0 on success, >0 if an error occurred. SEE ALSO
cmp(1), diff(1), sort(1), uniq(1) STANDARDS
The comm utility conforms to IEEE Std 1003.2-1992 (``POSIX.2''). BSD
June 6, 1993 BSD
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