help with awk script Post: 302565779

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Unable to pass shell script parameter value to awk command in side the same script

Variable I have in my shell script diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new I could see value of $id is not passing to the awk...

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Passing shell script parameter value to awk command in side the script

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LEARN ABOUT OSX

colrm

COLRM(1)						    BSD General Commands Manual 						  COLRM(1)

NAME

     colrm -- remove columns from a file

SYNOPSIS

     colrm [start [stop]]

DESCRIPTION

     The colrm utility removes selected columns from the lines of a file.  A column is defined as a single character in a line.  Input is read
     from the standard input.  Output is written to the standard output.

     If only the start column is specified, columns numbered less than the start column will be written.  If both start and stop columns are spec-
     ified, columns numbered less than the start column or greater than the stop column will be written.  Column numbering starts with one, not
     zero.

     Tab characters increment the column count to the next multiple of eight.  Backspace characters decrement the column count by one.

ENVIRONMENT

     The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).

EXIT STATUS

     The colrm utility exits 0 on success, and >0 if an error occurs.

SEE ALSO

     awk(1), column(1), cut(1), paste(1)

HISTORY

     The colrm command appeared in 3.0BSD.

BSD
								  August 4, 2004							       BSD

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