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Top Forums Shell Programming and Scripting Multiple If statements in bash problem Post 302565479 by Ophiuchus on Tuesday 18th of October 2011 04:16:08 AM
Old 10-18-2011
Hi anchal_kare,

I receive syntax errors. I've tried both ways, like in my first post and using comparison operators as you suggest me.
Code:
X=10
if [[ "$X" -le 5 ]]; then
    echo "The value is between 1 and 5"
    for ((i=1;i<=${X})); do
     echo $i
    done 
else if [[ "$X" -gt 5 && "$X" -le 10 ]]; then
    echo "The value is between 6 and 10"
    for ((i=1;i<=${X})); do
     echo $i
    done 
else if [[  "$X" -gt 10 &&  "$X" -le 20 ]]; then
    echo "The value is between 10 and 20"
    for ((i=1;i<=${X})); do
     echo $i
    done 
fi

But I continue receiving syntax errors
-syntax error near of unexpected element "fi"
- it requires an arithmetic expression
- syntax error near of ";"

Thanks for your help
 

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IN_ARRAY(3)								 1							       IN_ARRAY(3)

in_array - Checks if a value exists in an array

SYNOPSIS
bool in_array FALSE (mixed $needle, array $haystack, [bool $strict]) DESCRIPTION
Searches $haystack for $needle using loose comparison unless $strict is set. PARAMETERS
o $needle - The searched value. Note If $needle is a string, the comparison is done in a case-sensitive manner. o $haystack - The array. o $strict - If the third parameter $strict is set to TRUE then the in_array(3) function will also check the types of the $needle in the $haystack. RETURN VALUES
Returns TRUE if $needle is found in the array, FALSE otherwise. EXAMPLES
Example #1 in_array(3) example <?php $os = array("Mac", "NT", "Irix", "Linux"); if (in_array("Irix", $os)) { echo "Got Irix"; } if (in_array("mac", $os)) { echo "Got mac"; } ?> The second condition fails because in_array(3) is case-sensitive, so the program above will display: Got Irix Example #2 in_array(3) with strict example <?php $a = array('1.10', 12.4, 1.13); if (in_array('12.4', $a, true)) { echo "'12.4' found with strict check "; } if (in_array(1.13, $a, true)) { echo "1.13 found with strict check "; } ?> The above example will output: 1.13 found with strict check Example #3 in_array(3) with an array as needle <?php $a = array(array('p', 'h'), array('p', 'r'), 'o'); if (in_array(array('p', 'h'), $a)) { echo "'ph' was found "; } if (in_array(array('f', 'i'), $a)) { echo "'fi' was found "; } if (in_array('o', $a)) { echo "'o' was found "; } ?> The above example will output: 'o' was found SEE ALSO
array_search(3), isset(3), array_key_exists(3). PHP Documentation Group IN_ARRAY(3)
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