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Full Discussion: memcpy error
Top Forums Programming memcpy error Post 302564699 by alister on Friday 14th of October 2011 11:31:05 AM
Old 10-14-2011
Quote:
Originally Posted by rajsekhar28
char *finalptr = ( char *)malloc(1048576* sizeof(char));
Unrelated to the segfault, there are a couple of things about this statement of which you should be aware.

In general, if you're going to multiply a number by the size of a data type, you should use calloc(). If not, you should check for overflow before passing the result to malloc(). I say in general because in this specific instance, where the number is hardcoded and the product is almost certainly less than the max value of size_t, it's extremely unlikely that it will cause a problem.

Unless you know why you're doing it, it's best not to cast unnecessarily. Many C programmers do it unthinkningly, but it is a practice with zero benefit and a potentially insidious drawback: supression of compiler warnings and errors.

If the malloc implementation does not return void * (or in this instance * char), the explicit cast tells the compiler that its okay if malloc returns an int (which is not unheard of) or some other type, and, should such a mismatch occur, that you want it to silently coerce the return value regardless of its type. Such coercion can lead to unexpected behavior.

Regards,
Alister
 

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MALLOC(3)						   BSD Library Functions Manual 						 MALLOC(3)

NAME
malloc, calloc, realloc, free -- general purpose memory allocation functions LIBRARY
Standard C Library (libc, -lc) SYNOPSIS
#include <stdlib.h> void * malloc(size_t size); void * calloc(size_t number, size_t size); void * realloc(void *ptr, size_t size); void free(void *ptr); DESCRIPTION
The malloc() function allocates size bytes of uninitialized memory. The allocated space is suitably aligned (after possible pointer coer- cion) for storage of any type of object. The calloc() function allocates space for number objects, each size bytes in length. The result is identical to calling malloc() with an argument of ``number * size'', with the exception that the allocated memory is explicitly initialized to zero bytes. The realloc() function changes the size of the previously allocated memory referenced by ptr to size bytes. The contents of the memory are unchanged up to the lesser of the new and old sizes. If the new size is larger, the value of the newly allocated portion of the memory is undefined. Upon success, the memory referenced by ptr is freed and a pointer to the newly allocated memory is returned. Note that realloc() may move the memory allocation, resulting in a different return value than ptr. If ptr is NULL, the realloc() function behaves identically to malloc() for the specified size. The free() function causes the allocated memory referenced by ptr to be made available for future allocations. If ptr is NULL, no action occurs. RETURN VALUES
The malloc() and calloc() functions return a pointer to the allocated memory if successful; otherwise a NULL pointer is returned and errno is set to ENOMEM. The realloc() function returns a pointer, possibly identical to ptr, to the allocated memory if successful; otherwise a NULL pointer is returned, and errno is set to ENOMEM if the error was the result of an allocation failure. The realloc() function always leaves the original buffer intact when an error occurs. The free() function returns no value. EXAMPLES
When using malloc(), be careful to avoid the following idiom: if ((p = malloc(number * size)) == NULL) err(EXIT_FAILURE, "malloc"); The multiplication may lead to an integer overflow. To avoid this, calloc() is recommended. If malloc() must be used, be sure to test for overflow: if (size && number > SIZE_MAX / size) { errno = EOVERFLOW; err(EXIT_FAILURE, "allocation"); } When using realloc(), one must be careful to avoid the following idiom: nsize += 50; if ((p = realloc(p, nsize)) == NULL) return NULL; Do not adjust the variable describing how much memory has been allocated until it is known that the allocation has been successful. This can cause aberrant program behavior if the incorrect size value is used. In most cases, the above example will also leak memory. As stated ear- lier, a return value of NULL indicates that the old object still remains allocated. Better code looks like this: newsize = size + 50; if ((p2 = realloc(p, newsize)) == NULL) { if (p != NULL) free(p); p = NULL; return NULL; } p = p2; size = newsize; SEE ALSO
madvise(2), mmap(2), sbrk(2), alloca(3), atexit(3), getpagesize(3), memory(3), posix_memalign(3) For the implementation details, see jemalloc(3). STANDARDS
The malloc(), calloc(), realloc() and free() functions conform to ISO/IEC 9899:1990 (``ISO C90''). BSD
May 3, 2010 BSD
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