okay, i confused it.. here is the text file
you can see that field f3 has a new line character in it.. but i want ~~\n as row delimiter adn so it should count to 3.
somehow awk doesn't take multiple character as field or row delimiters.? how do i that?
I have a flat file and need to count no of records in the file less the header and the trailer record.
I would appreciate any and all asistance
Thanks
Hadi Lalani (2 Replies)
I need to count the number of files which have a search string, but counting the file only once
if search string is found.
eg: File1: Please note that there are 2 occurances of "aaa"
aaa
bbb
ccc
aaa
File2: Please note that there are 3 occurances of "aaa"
aaa
bbb
ccc... (1 Reply)
Hi All,
I have a delimited file.Sometime it happens that delimiter get missed between 2 fields,so i need to count the number of delimiter present at each line.
exam
file.txt
a|b|c|d
e|f|a
cc|dd
so output should be
1 3
2 2
3 1
Thanks (2 Replies)
Hi,
I am trying out different scripts in PERL. I want to take a line/string as an input from the user and count the number of occurrances of all the alphabets (a..z) in the string. I tried doingit like this :
#! /opt/exp/bin/perl
print "Enter a string or line : ";
$string = <STDIN>;
chop... (5 Replies)
I've been working with an awk script and I'm wondeing id it's possible to count records in a file which DO NOT contain, in this instance fields 12 and 13.
With the one script I am wanting to display the count for the records WITH fields 12 and 13 and a seperate count of records WITHOUT fields... (2 Replies)
Hi,
Please help me in counting the below records(1st field) from samplefile:
Expected output:
Count Descr
-------------------------------------------
7 Mean manager
14 ... (7 Replies)
I’m new to Linux script and not sure how to filter out bad records from huge flat files (over 1.3GB each). The delimiter is a semi colon “;”
Here is the sample of 5 lines in the file:
Name1;phone1;address1;city1;state1;zipcode1
Name2;phone2;address2;city2;state2;zipcode2;comment... (7 Replies)
i need to be able to count the number of single quotes ' in the entire string below:
"description":"DevOps- Test VM's, System Admins Test VM's ",
awk can most likely do this, but here's my attempt using egrep:
echo "${STRING}" | egrep -wc '"'"\'"'"'
or
echo "${STRING}" | egrep -wc... (11 Replies)
we want the count of number of records to be printed on each row.
For Ex:
if there are 5 records on one unique id , the count "5'' should be printed on each record in other column. Please help for this. I am using unix & Cygwin.
Below are sample records:
KCZ0650473... (2 Replies)
Discussion started by: ElijaRajesh
2 Replies
LEARN ABOUT PHP
preg_quote
PREG_QUOTE(3) 1 PREG_QUOTE(3)preg_quote - Quote regular expression charactersSYNOPSIS
string preg_quote NULL (string $str, [string $delimiter])
DESCRIPTION preg_quote(3) takes $str and puts a backslash in front of every character that is part of the regular expression syntax. This is useful if
you have a run-time string that you need to match in some text and the string may contain special regex characters.
The special regular expression characters are: . + * ? [ ^ ] $ ( ) { } = ! < > | : -
PARAMETERS
o $str
- The input string.
o $delimiter
- If the optional $delimiter is specified, it will also be escaped. This is useful for escaping the delimiter that is required by
the PCRE functions. The / is the most commonly used delimiter.
RETURN VALUES
Returns the quoted (escaped) string.
CHANGELOG
+--------+--------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+--------------------------------+
| 5.3.0 | |
| | |
| | The - character is now quoted |
| | |
+--------+--------------------------------+
EXAMPLES
Example #1
preg_quote(3) example
<?php
$keywords = '$40 for a g3/400';
$keywords = preg_quote($keywords, '/');
echo $keywords; // returns $40 for a g3/400
?>
Example #2
Italicizing a word within some text
<?php
// In this example, preg_quote($word) is used to keep the
// asterisks from having special meaning to the regular
// expression.
$textbody = "This book is *very* difficult to find.";
$word = "*very*";
$textbody = preg_replace ("/" . preg_quote($word, '/') . "/",
"<i>" . $word . "</i>",
$textbody);
?>
NOTES
Note
This function is binary-safe.
SEE ALSO
PCRE Patterns, escapeshellcmd(3).
PHP Documentation Group PREG_QUOTE(3)