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Top Forums Shell Programming and Scripting How to get line after occurence of sequence of patterns Post 302563781 by ahamed101 on Wednesday 12th of October 2011 06:59:10 AM
Old 10-12-2011
I suppose you meant the output should be line2?

Try this...
Code:
sed -n 'H;/pattern4/{x;/pattern1.*pattern2.*pattern3/{n;n;p}}' input_file

--ahamed
 

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STRSUB(3pub)						       C Programmer's Manual						      STRSUB(3pub)

NAME
strsub - substitute first occurence of pattern with another string SYNOPSIS
#include <publib.h> char *strsub(char *str, const char *pat, const char *sub); DESCRIPTION
strsub finds the first occurence of the pattern pat in the string str (using a method similar to strstr(3), i.e., no regular expressions), and replaces it with sub. If pat does not occur in str, no substitution is made. Of course, if sub is an empty string, the pattern is deleted from the string. RETURN VALUE
strsub returns a pointer to the first character after the substitution, or NULL if no substitution was made. EXAMPLE
To substitute up to two occurences of "foo" with "bar" in a line, one might do the following. p = strsub(line, "foo", "bar"); if (p != NULL) strsub(line, "foo", "bar"); SEE ALSO
publib(3), strstr(3), strgsub(3) AUTHOR
Lars Wirzenius (lars.wirzenius@helsinki.fi) Publib C Programmer's Manual STRSUB(3pub)
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