Sponsored Content
Top Forums UNIX for Dummies Questions & Answers Variable inside command substitution Post 302561423 by drbiloukos on Tuesday 4th of October 2011 05:46:08 AM
Old 10-04-2011
Variable inside command substitution

Hello people.

Part of my script:

Code:
 
SUBSETID=`echo $PMFILE |sed 's/pmresult_//' | sed 's/_[^ ]*//'`
 
MAPFILE=`find /huawei/cell /huawei/nodeb /huawei/rnc -name 'mapping_$SUBSETID.txt' |grep -v backup`

Unfortunatelly variable $SUBSETID in the MAPFILE declaration will not return the value causing the script to freeze.

Please advice how to overcome.

Thank you in advance.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

sed insert command and variable expansion/command substitution

I know this script is crummy, but I was just messing around.. how do I get sed's insert command to allow variable expansion to show the filename? #!/bin/bash filename=`echo $0` /usr/bin/sed '/#include/ { i\ the filename is `$filename` }' $1 exit 0 (8 Replies)
Discussion started by: glev2005
8 Replies

2. Shell Programming and Scripting

Making script show command (e.g. copy) being executed and variable substitution?

When script is running you only see when some of the commands are not successfull. Is there a way to see which command are executed and to show the substitution of variables as every line is executed ? (3 Replies)
Discussion started by: gr0124
3 Replies

3. Shell Programming and Scripting

How to use variable with command substitution in variable

For example I have variable like below echo $OUTPUT /some/path/`uname -n` when I try to use the variable OUTPUT like below cd $OUTPUT or cd ${OUTPUT} I am getting bad substituion error message $ cd $OUTPUT ksh: cd: bad substitution $ cd ${OUTPUT} ksh: cd: bad substitution ... (1 Reply)
Discussion started by: rajukv
1 Replies

4. Shell Programming and Scripting

How to use same variable value inside as well as outside of the awk command?

Hi Jim, The following script is in working state. But i m having one more problem with awk cmd. Could you tell me how to use any variable inside awk or how to take any variable value outside awk. My problem is i want to maintain one property file in which i am declaring variable value into that... (12 Replies)
Discussion started by: Ganesh Khandare
12 Replies

5. Shell Programming and Scripting

Not able to store command inside a shell variable, and run the variable

Hi, I am trying to do the following thing var='date' $var Above command substitutes date for and in turn runs the date command and i am getting the todays date value. I am trying to do the same thing as following, but facing some problems, unique_host_pro="sed -e ' /#/d'... (3 Replies)
Discussion started by: gvinayagam
3 Replies

6. Shell Programming and Scripting

[Solved] Command Substitution and Variable Expansion within a Case

Hello All, I don't write scripts very often, and in this case I am stumped, although it may be a bug in the version of bash I have to use (it's not my system). I want to extract a specific string snippet from a block of text (coming from a log file) that is dependent on a bunch of other... (1 Reply)
Discussion started by: jaimielives
1 Replies

7. Shell Programming and Scripting

How i can put the result of a command inside a bash variable?

#!/bin/bash #... for i in `ls -c1 /usr/share/applications` do name="cat $i | grep ^Name= | cut -d = -f2" echo $name #... done Now inside name as output is present: while i want only the result of the command. Ideally i would like obtain that information using only bash ... or... (8 Replies)
Discussion started by: alexscript
8 Replies

8. Shell Programming and Scripting

Command substitution inside of a variable expression (AIX, KORN)

Hello all. This is my first post/question on this site. I’m a new Systems Analyst with previous experience with BASH. Although now I'm using AIX, and I’m trying to get a feel for the Korn shell (for those of you that don’t know AIX only uses the KORN shell). I hope I put this into the correct... (10 Replies)
Discussion started by: sydox
10 Replies

9. Shell Programming and Scripting

Variable inside -name option for find command

Hi, I am not able to get output for find command if there are variables defined inside -name option . Please check below example 1) ###VARIABLES DEFINED process="fast" temperature="125c" voltage="0p935v" 2) I don't get output for below find command find -L <PATH> -type f \( -name... (2 Replies)
Discussion started by: gujrathinr
2 Replies

10. Shell Programming and Scripting

Store command inside variable

Is it possible to store a command inside a variable? i want this piece to be stored inside a variable, so i can use it later in a different command $u | cut -d " " -f 2 var="$u | cut -d " " -f 2" eval $var I tried to use eval but I receive this error: -f 2: command not found ... (5 Replies)
Discussion started by: velos
5 Replies
bup-margin(1)						      General Commands Manual						     bup-margin(1)

NAME
bup-margin - figure out your deduplication safety margin SYNOPSIS
bup margin [options...] DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids. For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by its first 46 bits. The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits, that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits with far fewer objects. If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if you're getting dangerously close to 160 bits. OPTIONS
--predict Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer from the guess. This is potentially useful for tuning an interpolation search algorithm. --ignore-midx don't use .midx files, use only .idx files. This is only really useful when used with --predict. EXAMPLE
$ bup margin Reading indexes: 100.00% (1612581/1612581), done. 40 40 matching prefix bits 1.94 bits per doubling 120 bits (61.86 doublings) remaining 4.19338e+18 times larger is possible Everyone on earth could have 625878182 data sets like yours, all in one repository, and we would expect 1 object collision. $ bup margin --predict PackIdxList: using 1 index. Reading indexes: 100.00% (1612581/1612581), done. 915 of 1612581 (0.057%) SEE ALSO
bup-midx(1), bup-save(1) BUP
Part of the bup(1) suite. AUTHORS
Avery Pennarun <apenwarr@gmail.com>. Bup unknown- bup-margin(1)
All times are GMT -4. The time now is 02:58 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy