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Full Discussion: Array output through a for loop problematic with multiple elements.
Top Forums Shell Programming and Scripting Array output through a for loop problematic with multiple elements. Post 302560773 by alister on Saturday 1st of October 2011 04:46:33 AM
Old 10-01-2011
Previously, I simply pointed out what stood out without giving the purpose of your code much thought. I seldom use linux (or bash), so after googling for a sample of linux's ifconfig output, here's how I'd do what I think you're trying to do:
Code:
#!/bin/sh

if [ 5.21 = $(nmap --version | awk '/Nmap/ { print $3 }') ]; then
    i=5  t=report    # field index and target text
else
    i=2  t=Host
fi

/sbin/ifconfig | awk '/inet addr/ && !/127.0.0.1/ && !a[$2]++ {print substr($2,6)}' |
    while read ip; do
          nmap -sP ${ip%.*}.0/24 | awk 'index($0,t) { print $i }' t="$t" i="$i"
          sleep 1
    done

The ifconfig|awk pipe feeding the while loop should output full ip addresses (all 4 octets) one per line. ${ip%.*}.0/24 strips the final octet and replaces it with 0 and the /24 cidr prefix.

If that doesn't work, then perhaps someone who has linux and nmap handy can help.

Regards,
Alister

---------- Post updated at 04:46 AM ---------- Previous update was at 04:32 AM ----------

In my first post, $2!="127.0.0.1" isn't eliminating the loopback address because it's trying to match an entire field whose value is that ip address. It didn't take into account that in the linux ifconfig output, the actual value of $2 would be addr:127.0.0.1.

Regards,
Alister
Last edited by alister; 10-01-2011 at 05:41 AM..
This User Gave Thanks to alister For This Post:
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