I am running a command to extract data from a database which has different text and dates (ex. 01/03/07, 05/29/08, 06/05/08). Once the file is created I need to grep for all the text with a current date then redirect the sorted data to another file then email the file out. Here is what I have right... (2 Replies)
Hi,
I have logfile like this :
Actually the format is date format :
yyyymmddHHMMSS
and i want the log become this format
yyyy-mm-dd HH:MM:SS
for example
2009-07-19 11:46:52
Can somebody help me ?
Thanks in advance (3 Replies)
I have a file that is a log file for web traffic. I would like to convert the timestamp in it to unix time or epoch time.
I am using the date command in conjunction with awk to try to do this. Just
myfile:
28/Aug/1995:00:00:38 1 /pub/atomicbk/catalog/home.gif 813
28/Aug/1995:00:00:38 1... (3 Replies)
Hi all;
I am running a script:/var/tmp/gcsw -ne | grep "State:2" | wc
that gives me output like:80 480 6529
but i need this output as:2013-01-18 13:00 -> 80 480 6529 (1 Reply)
Hi All
I need to get the date from a file.
my file a.out has the below data:
INFO : LM_36435 : (10153|1400211776)
Starting execution of workflow in folder
last saved by user .
The date here is Sun Jun 17 05:00:05 2013 ,which is the system date and keep on changing everyday.
So... (8 Replies)
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
Hello guys. i have problem to execute the:
DT=$(date +"%Y%m%d");
command in awk script. i wrote this script:
#bin/bash
BEGIN{
FS=""
DT=$(date +"%Y%m%d");
FullBackupValue=0;
LevelBackupValue=0;
ControlBackupValue=0;
ArchBackupValue=0;
}
{
if($1 == "full" &&... (4 Replies)
Hi,
I have been stuck in this requirement where my file contains the below format.
20150812170500846959990854-25383-8.0.0
"ABC Report" hp96880
"4952"
20150812170501846959990854-25383-8.0.0 End of run
20150812060132846959990854-20495-8.0.0
"XYZ Report" vg76452
"1006962188"... (6 Replies)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT PHP
datetimeinterface.format
DATETIMEINTERFACE.FORMAT(3) 1 DATETIMEINTERFACE.FORMAT(3)DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTimeInterface.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO date(3).
PHP Documentation Group DATETIMEINTERFACE.FORMAT(3)