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Full Discussion: awk command with date
Top Forums Shell Programming and Scripting awk command with date Post 302556984 by Scott on Tuesday 20th of September 2011 09:00:13 AM
Old 09-20-2011
Not too sure either what you plan to do with it, but you can get the desired output with sed.

Code:
$ sed 's/$/_`date "+%Y-%m-%d"`/' file1 > file2
/tmp/test1_`date "+%Y-%m-%d"`
/tmp/test2_`date "+%Y-%m-%d"`
/tmp/test3_`date "+%Y-%m-%d"`

A fix for your awk:
Code:
$ awk '{print $0 "_`date \"+%Y-%m-%d\"`"}' file1
/tmp/test1_`date "+%Y-%m-%d"`
/tmp/test2_`date "+%Y-%m-%d"`
/tmp/test3_`date "+%Y-%m-%d"`


Last edited by Scott; 09-20-2011 at 10:11 AM.. Reason: Added AWK
 

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DATETIMEINTERFACE.FORMAT(3)						 1					       DATETIMEINTERFACE.FORMAT(3)

DateTime::format - Returns date formatted according to given format

       Object oriented style

SYNOPSIS
public string DateTime::format (string $format) DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format) Procedural style string date_format (DateTimeInterface $object, string $format) Returns date formatted according to given format. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3) o $format - Format accepted by date(3). RETURN VALUES
Returns the formatted date string on success or FALSE on failure. EXAMPLES
Example #1 DateTimeInterface.format(3) example Object oriented style <?php $date = new DateTime('2000-01-01'); echo $date->format('Y-m-d H:i:s'); ?> Procedural style <?php $date = date_create('2000-01-01'); echo date_format($date, 'Y-m-d H:i:s'); ?> The above example will output: 2000-01-01 00:00:00 NOTES
This method does not use locales. All output is in English. SEE ALSO
date(3). PHP Documentation Group DATETIMEINTERFACE.FORMAT(3)
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