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Top Forums Shell Programming and Scripting replace (sed?) a string in file with multiple lines (string) from variable Post 302555688 by jforce on Thursday 15th of September 2011 10:10:41 AM
Old 09-15-2011
Quote:
Originally Posted by birei
Hi,

Use double quotes for the entire 'sed' command.
Code:
$ sed -i "s/STRING/$a/g" filename.ext

Regards,
Birei
I try double quotes but don't work

In my case
a=$(ewrwertwer trt erter ter ter tyer terter terter ter (werrewr) rwerwer werwer
asdas asd asd asd
werwerrweéé wéé)

Last edited by jforce; 09-15-2011 at 06:25 PM..
 

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ESCAPESHELLARG(3)							 1							 ESCAPESHELLARG(3)

escapeshellarg - Escape a string to be used as a shell argument

SYNOPSIS
string escapeshellarg (string $arg) DESCRIPTION
escapeshellarg(3) adds single quotes around a string and quotes/escapes any existing single quotes allowing you to pass a string directly to a shell function and having it be treated as a single safe argument. This function should be used to escape individual arguments to shell functions coming from user input. The shell functions include exec(3), system(3) and the backtick operator. On Windows, escapeshellarg(3) instead removes percent signs, replaces double quotes with spaces and adds double quotes around the string. PARAMETERS
o $arg - The argument that will be escaped. RETURN VALUES
The escaped string. EXAMPLES
Example #1 escapeshellarg(3) example <?php system('ls '.escapeshellarg($dir)); ?> SEE ALSO
escapeshellcmd(3), exec(3), popen(3), system(3), backtick operator. PHP Documentation Group ESCAPESHELLARG(3)
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